我从python实现获得的HMAC SHA1签名和我的clojure实现略有不同。我很难过会导致这种情况。
Python实现:
import hashlib
import hmac
print hmac.new("my-key", "my-data", hashlib.sha1).hexdigest() # 8bcd5631480093f0b00bd072ead42c032eb31059
Clojure实施:
(ns my-project.hmac
(:import (javax.crypto Mac)
(javax.crypto.spec SecretKeySpec)))
(def algorithm "HmacSHA1")
(defn return-signing-key [key mac]
"Get an hmac key from the raw key bytes given some 'mac' algorithm.
Known 'mac' options: HmacSHA1"
(SecretKeySpec. (.getBytes key) (.getAlgorithm mac)))
(defn sign-to-bytes [key string]
"Returns the byte signature of a string with a given key, using a SHA1 HMAC."
(let [mac (Mac/getInstance algorithm)
secretKey (return-signing-key key mac)]
(-> (doto mac
(.init secretKey)
(.update (.getBytes string)))
.doFinal)))
; Formatting
(defn bytes-to-hexstring [bytes]
"Convert bytes to a String."
(apply str (map #(format "%x" %) bytes)))
; Public functions
(defn sign-to-hexstring [key string]
"Returns the HMAC SHA1 hex string signature from a key-string pair."
(bytes-to-hexstring (sign-to-bytes key string)))
(sign-to-hexstring "my-key" "my-data") ; 8bcd563148093f0b0bd072ead42c32eb31059
答案 0 :(得分:6)
将Clojure代码转换为十六进制字符串的部分会丢弃前导零。
您可以使用保持前导零("%02x"
)的格式字符串,或使用正确的十六进制编码库,例如Guava或Commons Codec。