如何结合签名略有不同的两种方法?

时间:2019-03-02 02:44:27

标签: c# .net

请考虑以下2种方法。主体是相同的-唯一的区别是方法的第二个参数(矩形与矩形F)。有没有一种方法可以将这两种方法合并为一种,而不必使参数列表复杂化:

public static void DrawRectangles(this Image thisImage, List<RectangleF> rectangles, Color color) {
  using (var g = Graphics.FromImage(thisImage)) {
    var brush = new SolidBrush(color);
    g.FillRectangles(brush, rectangles.ToArray());
  }
}

public static void DrawRectangles(this Image thisImage, List<Rectangle> rectangles, Color color) {
  using (var g = Graphics.FromImage(thisImage)) {
    var brush = new SolidBrush(color);
    g.FillRectangles(brush, rectangles.ToArray());
}

3 个答案:

答案 0 :(得分:3)

这是我认为可以减少代码重复的最佳方法:

private static void DrawRectangles<T>(this Image thisImage, List<T> rectangles, Color color, Action<Graphics, Brush, T[]> fill)
{
    using (var g = Graphics.FromImage(thisImage))
    {
        var brush = new SolidBrush(color);
        fill(g, brush, rectangles.ToArray());
    }
}

public static void DrawRectangles(this Image thisImage, List<RectangleF> rectangles, Color color)
{
    thisImage.DrawRectangles(rectangles, color, (g, b, rs) => g.FillRectangles(b, rs));
}

public static void DrawRectangles(this Image thisImage, List<Rectangle> rectangles, Color color)
{
    thisImage.DrawRectangles(rectangles, color, (g, b, rs) => g.FillRectangles(b, rs));
}

答案 1 :(得分:2)

您可以尝试使用RectangleF.Implicit(Rectangle to RectangleF) Operator,让RectangleRectangleF,然后将其传递为参数。

https://docs.microsoft.com/en-us/dotnet/api/system.drawing.rectanglef.op_implicit?redirectedfrom=MSDN&view=netframework-4.7.2

public static void DrawRectangles(this Image thisImage, List<RectangleF> rectangles, Color color)
{
    using (var g = Graphics.FromImage(thisImage))
    {
        var brush = new SolidBrush(color);
        g.FillRectangles(brush, rectangles.ToArray());
    }
}

public static void DrawRectangles(this Image thisImage, List<Rectangle> rectangles, Color color)
{
    var rectangleFs = rectangles.Select(x => (RectangleF) x).ToList();
    DrawRectangles(thisImage, rectangleFs, color);
}

答案 2 :(得分:1)

您可以定义一个采用通用参数作为IEnumerable的通用方法。

然后我们将is作为对象进行转换,并获取其类型为Rectangle或RectangleF。根据该逻辑,然后绘制矩形。

    public static void DrawRectangles<T>(this Image thisImage, T rectangles, Color color) where T : IEnumerable
    {
        using (var g = Graphics.FromImage(thisImage))
        {
            var brush = new SolidBrush(color);
            if (rectangles.Cast<object>().FirstOrDefault().GetType() == typeof(Rectangle))
            {
                g.FillRectangles(brush, rectangles.Cast<Rectangle>().ToArray());
            }
            else
            {
                g.FillRectangles(brush, rectangles.Cast<RectangleF>().ToArray());
            }
        }
    }

    public static void Main(string[] args)
    {
        List<Rectangle> r = new List<Rectangle>();
        List<RectangleF> rf = new List<RectangleF>();

        r.Add(new Rectangle(10, 10, 10, 10));
        rf.Add(new RectangleF(10.4f, 10.4f, 10.4f, 10.4f));
        DrawRectangles(new Bitmap(10, 10), rf, Color.Aqua);
    }