Question

我通过UIWebView加载了html页面。如果用户选择的链接如下：

<a webview="2" href="#!/accounts-cards/<%= item.acctno %>"></a>

我可以从NSURLRequest的UIWebViewDelegate方法中点击href值：

webView:shouldStartLoadWithRequest:navigationType:

但是假设属性名称“webview”已确定，我如何从此超链接（webview =“ 2 ”）获取属性值？

Answer 1

您可以在JavaScript的帮助下获取属性“webview”，之后您可以将该属性及其值发送到本机Objective C代码。

将此JavaScript代码添加到脚本标记内的HTML页面中：

function reportBackToObjectiveC(string)
{
    var iframe = document.createElement("iframe");
    iframe.setAttribute("src", "callback://" + string);
    document.documentElement.appendChild(iframe);
    iframe.parentNode.removeChild(iframe);
    iframe = null;
}

var links = document.getElementsByTagName("a");
for (var i=0; i<links.length; i++) {
links[i].addEventListener("click", function() {
var attributeValue=links[i].webview; //this will give you your attribute(webview) value.
    reportBackToObjectiveC(attributeValue);
}, true);
}

之后你的webViewDelegate方法将调用：

- (BOOL)webView:(UIWebView *)wView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType{

{
    if (navigationType == UIWebViewNavigationTypeLinkClicked) 
    { 
        NSURL *URL = [request URL]; 
        if ([[URL scheme] isEqualToString:@"callback"])
        { 
            //You can get here your attribute's value.
        } 
}

Answer 2

您需要更改链接的href。首先注入javascript脚本，修补你的链接。

- (void)webViewDidFinishLoad:(UIWebView *)webView 
{

    NSString *js = @"var allElements = document.getElementsByTagName('a');"
                    "for (var i = 0; i < allElements.length; i++) {"
                    "    attribute = allElements[i].getAttribute('webview');"
                    "    if (attribute) {"
                    "        allElements[i].href = allElements[i].href + '&' + attribute;"
                    "    }"
                    "}";
    [webView stringByEvaluatingJavaScriptFromString:js];

}

链接将转换为格式（href属性中的注释＆amp; 2）： <a webview="2" href="#!/accounts-cards/<%= item.acctno %>&2"></a> 然后你可以获得你的回调并解析你的webview参数值：

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
    NSArray *array = [request.URL.absoluteString componentsSeparatedByString:@"&"];
    if (array.count > 2) {
        NSLog(@"webview value = %@", array[1]);
    }
    return YES;
}

UIWebView：从点击的超链接获取属性

2 个答案: