我可以通过以下代码获取课程文本:
[webview stringByEvaluatingJavaScriptFromString:@"document.getElementsByClassName('normal fs16 bold c-red2')[0].innerHTML;"];
但我还需要获得此课程的链接。
答案 0 :(得分:0)
我刚刚解决了网站的所有链接并使用字符串:
[webView stringByEvaluatingJavaScriptFromString:@"var script = document.createElement('script');"
"script.type = 'text/javascript';"
"script.text = \"function getHyperlinks() { "
"var links = document.getElementsByTagName('a');"
"var allLinks = '';"
"for (var i = 0; i<links.length; i++) {"
"var link = links[i].href + '~' + links[i].text + '~' + links[i].title + ';';"
"allLinks += link;"
"} return allLinks;"
"}\";"
"document.getElementsByTagName('head')[0].appendChild(script);"];
NSString *html = [webView stringByEvaluatingJavaScriptFromString:
@"getHyperlinks();"];