Question

#This program generates random number
#user enters guess
#progam tells user higher, lower or correct based on user input.
import random

def main():
    # Get a random number.
    number = random.randint(1, 101)
    user_guess = int(input("Pick a number between 1 and 100: "))
    userguess = guess(user_guess, number)
    print(userguess)


def guess(num1, num2):
    if num1 > num2:
        return("Lower")
    elif num1 < num2:
        return("Higher")
    else:
        return("Correct")

main（）的

我可以让程序生成一个随机数，然后显示更高或更低，但不再显示。它应该再次询问，直到它击中随机，然后显示'正确'

Answer 1

您需要一个循环来保持提示，直到猜到正确的答案为止，while(True)一直持续到break;为止。尝试这样的事情。

def guess(num):
    while(True):
        user_guess = int(input("Pick a number between 1 and 100: "))
        if user_guess > num:
            print("Lower\n")
        elif user_guess < num:
            print("Higher\n")
        else:
            print("Correct")
            break;

这将反复向用户询问数字，直到他们正确用以下

替换您的主要方法

def main():
    # Get a random number.
    number = random.randint(1, 101)
    guess(number)

编辑：用True替换为true

使用随机库来猜测数字（Python）

1 个答案: