Question

我有这个基本代码，我想要它做的是选择一个随机数，然后它会要求用户输入一个从0到100的数字，它会根据数字给出结果，例如数字是太低或太高。我一直在切换，但总是会出错，这对于2.7：

import random
randomNumber = random.randrange(0,100)
guess = -1
guess = int(input('Enter a number between 0 and 100: ')
guess != randomNumber:
if guess < randomNumber
    print('Your guess is too low.')
elif guess > randomNumber:
    print('Your guess is too high.')
print('You win!')

Answer 1

首先，您定义guess两次。只需定义一次。如果它不是原始值，则无需使guess等于-1。其次，我相信您想使用while循环来检查用户是否猜到了正确的数字。在这种情况下，将另一个guess添加到while循环中，以允许玩家继续猜测并保持正确的语法。

不要让玩家在另一个条件下获胜。在每个if/elif语句后也使用冒号。在比较字符串（输入）和整数时，请将input()更改为int(input())。最终的代码应该是这样的：

import random

randomNumber = random.randrange(0, 100)
guess = None                                   # Define guess

while guess != randomNumber:                   # Create loop 
    guess = int(input("Enter a number between 0 and 100"))   # Change guess
    if guess < randomNumber:
        print "Your guess is too low."
    elif guess > randomNumber:
        print "Your guess is too high."
    elif guess == randomNumber:
        print "You win!"                        # Win message under correct condition
        break                                   # Exit the loop as game is finished

Answer 2

你的if语句后缺少一个冒号。无论结果如何，您还打印You win!。把它放在else语句中。您不需要此行guess != randomNumber:，并且您不需要guess=-1，最后您会错过评论中提到的结束语。

import random
randomNumber = random.randrange(0,100)
guess = None
while guess != randomNumber:
    guess = int(input('Enter a number between 0 and 100: '))
    if guess == randomNumber:
        break
    elif guess < randomNumber:
        print('Your guess is too low.')
    elif guess > randomNumber:
        print('Your guess is too high.')
print('You win!')

Answer 3

（编辑 - 删除了一些不必要的行）

缺少一些格式化，并且有几行（猜测！= randomNumber :)并没有真正做任何事情（在这种情况下，冒号会导致语法错误。）

import random

randomNumber = random.randrange(0,100)

guess = int(input('Enter a number between 0 and 100: '))

if guess < randomNumber:
    print('Your guess is too low.')
elif guess > randomNumber:
    print('Your guess is too high.')
else: # assuming you only want to print this if they guessed right
    print('You win!')

Answer 4

像往常一样，评论您的代码会立即显示错误

import random

# Pick a number between 0 and 99
randomNumber = random.randrange(0,100)

# initialize guess  (hint: why?)
guess = -1

# Ask the user to guess a number  (hint: balanced parentheses help)
guess = int(input('Enter a number between 0 and 100: ')

# What is this line supposed to be? Looks like the beginning of a loop here, but what kind?
guess != randomNumber:
# If the guess is less than the number, then tell the user
if guess < randomNumber
    print('Your guess is too low.')
# Otherwise if the guess is higher than the number, tell the user
elif guess > randomNumber:
    print('Your guess is too high.')

# Regardless, win the game. Wait whuh..?
print('You win!')

Answer 5

请尝试以下代码：

import random
randomNumber = random.randrange(0,100)
guess = int(input("Enter a number between 0 and 100:"))
if guess < randomNumber:
    print('Your guess is too low.')
elif guess > randomNumber:
    print('Your guess is too high.')
else:
    print('You win!')

随机数发生器，数字猜测。我的代码出了什么问题？

5 个答案: