Question

这是Python中的工作代码（使用cURL）：

#!/usr/bin/python

import pycurl

c = pycurl.Curl()
values = [
          ("key", "YOUR_API_KEY"),
          ("image", (c.FORM_FILE, "file.png"))]
# OR:     ("image", "http://example.com/example.jpg"))]
# OR:     ("image", "BASE64_ENCODED_STRING"))]

c.setopt(c.URL, "http://imgur.com/api/upload.xml")
c.setopt(c.HTTPPOST, values)

c.perform()
c.close()

这就是我在C＃中所拥有的：

public void UploadImage()
    {
        //I think this line is doing something wrong.
        //byte[] x = File.ReadAllBytes(@"C:\Users\Sergio\documents\visual studio 2010\Projects\WpfApplication1\WpfApplication1\Test\hotness2.jpg");

        //If I do it like this, using a direct URL everything works fine.
        string parameters = @"key=1b9189df79bf3f8dff2125c22834210903&image=http://static.reddit.com/reddit.com.header.png"; //Convert.ToBase64String(x);
        WebRequest webRequest = WebRequest.Create(new Uri("http://imgur.com/api/upload"));

        webRequest.ContentType = "application/x-www-form-urlencoded";
        webRequest.Method = "POST";
        byte[] bytes = Encoding.ASCII.GetBytes(parameters);

        Stream os = null;
        try
        { // send the Post
            webRequest.ContentLength = bytes.Length;   //Count bytes to send
            os = webRequest.GetRequestStream();
            os.Write(bytes, 0, bytes.Length);         //Send it
        }
        catch (WebException ex)
        {
            MessageBox.Show(ex.Message, "HttpPost: Request error");

        }
        finally
        {
            if (os != null)
            {
                os.Close();
            }
        }

        try
        { // get the response
            WebResponse webResponse = webRequest.GetResponse();

            StreamReader sr = new StreamReader(webResponse.GetResponseStream());
            MessageBox.Show(sr.ReadToEnd().Trim());
        }
        catch (WebException ex)
        {
            MessageBox.Show(ex.Message, "HttpPost: Response error");                  
        }            

    }

现在，我注意到的事情是，当我将参数字符串中的API密钥更改为“239231”或任何数字时，我得到的响应是：“无效的API密钥。”所以我觉得有些事情必须正确。

我放置了正确的 API密钥，现在我得到了不同的回复：“图片格式无效。请尝试上传JPEG图片。”

我正在使用的服务几乎接受所有图像格式，所以我100％肯定错误是我发送文件的方式。任何人都能解释一下吗？

修改!!!

事实证明，当我上传JPG图像时，我得到了那个灰盒子的东西。如果我上传一个大jpg图像我什么都没得到。例如：http://i.imgur.com/gFsUY.jpg

当我上传PNG时，上传的图片甚至都没有显示。

我确定问题是编码。我该怎么办？

编辑2 !!!

现在我100％确定问题出在方法的第一行。 File.ReadAllBytes（）必须做错事。如果我上传了一个网址文件，那么每个工作都会很有效：http://imgur.com/sVH61.png

我想知道我应该使用什么编码。：S

Answer 1

您应该正确形成多部分POST请求。请在此处查看示例：Upload files with HTTPWebrequest (multipart/form-data)

Answer 2

试试这个：

string file = @"C:\Users\Sergio\documents\visual studio 2010\Projects\WpfApplication1\WpfApplication1\Test\Avatar.png";
string parameters = @"key=1df918979bf3f8dff2125c22834210903&image=" +
    Convert.ToBase64String(File.ReadAllBytes(file));

Answer 3

阅读API发布的图片

public IHttpActionResult UpdatePhysicianImage(HttpRequestMessage request)
    {
        try
        {
            var form = HttpContext.Current.Request.Form;
            var model = JsonConvert.DeserializeObject<UserPic>(form["json"].ToString());
            bool istoken = _appdevice.GettokenID(model.DeviceId);
            if (!istoken)
            {
                statuscode = 0;
                message = ErrorMessage.TockenNotvalid;
                goto invalidtoken;
            }
            HttpResponseMessage result = null;
            var httpRequest = HttpContext.Current.Request;
            if (httpRequest.Files.Count > 0)
            {
                var docfiles = new List<string>();
                foreach (string file in httpRequest.Files)
                {
                    var postedFile = httpRequest.Files[file];
                    // var filePath = uploadPath + postedFile.FileName;
                    //  string fileUrl = Utility.AbsolutePath("~/Data/User/" + model.UserId.ToString());
                    string fileUrl = Utility.AbsolutePath("~/" + Utility.UserDataFolder(model.UserId, "Document"));
                    if (!Directory.Exists(fileUrl))
                    {
                        Directory.CreateDirectory(fileUrl);
                        Directory.CreateDirectory(fileUrl + "\\" + "Document");
                        Directory.CreateDirectory(fileUrl + "\\" + "License");
                        Directory.CreateDirectory(fileUrl + "\\" + "Profile");
                    }
                    string imageUrl = postedFile.FileName;
                    string naviPath = Utility.ProfileImagePath(model.UserId, imageUrl);
                    var path = Utility.AbsolutePath("~/" + naviPath);
                    postedFile.SaveAs(path);
                    docfiles.Add(path);
                    if (model.RoleId == 2)
                    {
                        var doctorEntity = _doctorProfile.GetNameVideoChat(model.UserId);
                        doctorEntity.ProfileImagePath = naviPath;
                        _doctorProfile.UpdateDoctorUpdProfile(doctorEntity);
                    }
                    else
                    {
                        var patientEntity = _PatientProfile.GetPatientByUserProfileId(model.UserId);
                        patientEntity.TumbImagePath = naviPath;
                        _PatientProfile.UpdatePatient(patientEntity);
                    }
                }
                result = Request.CreateResponse(HttpStatusCode.Created, docfiles);
            }
            else
            {
                result = Request.CreateResponse(HttpStatusCode.BadRequest);
            }
        }
        catch (Exception e)
        {
            statuscode = 0;
            message = "Error" + e.Message;
        }
    invalidtoken:
        return Json(modeldata.GetData(statuscode, message));
    }

Answer 4

尝试更改： -

"application/x-www-form-urlencoded"

到

"multipart/form-data"

Answer 5

尝试将jpg的内容类型添加到多部分边界。

请参阅此uRL以获取示例（最后）

http://www.w3.org/TR/html401/interact/forms.html#h-17.13.4.2

Answer 6

在黑暗中拍摄，但可能会创建一个Image实例，将文件保存到Stream并使用它将字节读入数组然后上传。

如：

Image i = System.Drawing.Image.FromFile("wut.jpg");
Stream stm = new Stream();
System.Drawing.Imaging.Encoder myEncoder = System.Drawing.Imaging.Encoder.Quality;
System.Drawing.Imaging.EncoderParameters paramz = new System.Drawing.Imaging.EncoderParameters(1);
myEncoderParameter = new EncoderParameter(myEncoder, 100L);
paramz.Param[0] = myEncoderParameter;
i.Save(stm, System.Drawing.Imaging.ImageFormat.Jpeg, paramz);
/* I'm lazy: code for reading Stream into byte[] here */

使用C＃和WebRequest上传图像？

6 个答案: