Question

我是android的新手。这是我从服务中得到的Json有人请指点我如何在Session（共享首选项）中保存这个JSONResponse我已经在我的SessionManager类中定义了这个函数但是我无法保存它。 JSON：

{
    "message": "Successfully Logged In.",
    "auths": "KONG,KONG-Surveyor",
    "user": {
        "view_all_proposals": "0",
        "role_id": "1",
        "contact_no": "020 8547 4333 (x354)",
        "date_modified": "2013-10-10 10:58:56",
        "status": "ACTIVE",
        "profit_margin_limit": "100",
        "cash_code": "KHO",
        "date_created": "2013-02-03 06:41:41",
        "user_initials": "KHO",
        "password": "f10343d1dc8d44c8935b356aa3f8aae2",
        "id": "27",
        "first_name": "Kong",
        "username": "kong",
        "is_admin": "0",
        "address": "Technology Manager",
        "email": "kong.hoang@mrfsgroup.com",
        "proposal_review": "0",
        "last_name": "Hoang",
        "ldap_authentication": "1"
    },
    "status": true,
    "apkStatus": true,
    "apkFileDate": "2013-12-05 04:47:52",
    "apkFile": "2_SurveyAppNew.apk"
}

这是我在SessionManger类中定义的函数：

 public static void setUserObject(Context c, String userObject) {
        SharedPreferences pref = PreferenceManager
                .getDefaultSharedPreferences(c);
        SharedPreferences.Editor editor = pref.edit();
        editor.putString("userObject", userObject);
        editor.commit();
    }

    public static String getUserObject(Context ctx) {
        SharedPreferences pref = PreferenceManager
                .getDefaultSharedPreferences(ctx);
        String userObject = pref.getString("userObject", null);
        return userObject;
    }

Answer 1

您可以简单地将整个JSONObject作为字符串。像这样：

String response = httpClient.execute(postMethod, resonseHandler);// your json parsing method

JSONObject jsonObject = new JSONObject(response);

setUserObject(context, jsonObject.toString(),"json_response");

然后你可以像：

那样回复它

JSONObject jsonObj = new JSONObject(getUserObject(context),"json_response");

将您的方法更改为：

 public static void setUserObject(Context c, String userObject,String key) {
        SharedPreferences pref = PreferenceManager
                .getDefaultSharedPreferences(c);
        SharedPreferences.Editor editor = pref.edit();
        editor.putString(key, userObject);
        editor.commit();
    }

    public static String getUserObject(Context ctx,String key) {
        SharedPreferences pref = PreferenceManager
                .getDefaultSharedPreferences(ctx);
        String userObject = pref.getString(key, null);
        return userObject;
    }

书籍：

请查看Jaguar对this问题的回答。

好教程：

您可以找到最佳教程系列之一here。

视频Tutorial系列。

Answer 2

JSONObject jObject_Main = new JSONObject(jsonStrng);
String jsonStr = jObject_Main.getString(jsonStringName);
JSONObject jsonObject = new JSONObject(jsonStr);
String message=jsonObject.getString("message");

SharedPreferences pref = PreferenceManager
                .getDefaultSharedPreferences(c);
        SharedPreferences.Editor editor = pref.edit();
        editor.putString("message", message);
        editor.commit();

首先你应该将json字符串转换为json对象，并且基于jsonobject你可以使用json字符串。

如何使用Android Native在Session（SharedPreferences）中保存JSONResponse？

2 个答案: