Question

我想知道是否有一种比较两个整数数组的简单方法，并按顺序在第一个数组源中添加缺少的元素。

例子代码：

        //Two list [source , compare ]
        public int[] ListSource = new int[]{ 4,8,12,20,24,32 } ;
        public int[] ListToCompare = new int[] { 3, 8, 16, 16, 20, 24, 28, 32,36 };

        //If size of array is different , we resize the source
        if(ListSource.Length != ListToCompare.Length)
        {
            Array.Resize(ref ListSource, ListToCompare.Length);
        }

        // Compare and update
        for(int a = 0 ; a < ListToCompare.Length;a++)
        {
            if(ListSource[a] != ListToCompare[a])
            {
                // .... How can i do it 
            }
        }

        //And finally my Listsource is complete merge with the listToCompare and in good order
        //ListSource = { 3, 4, 8, 12, 16, 16, 20, 24, 28, 32 };

非常感谢： - ）

Answer 1

试试这个：

ListSource = ListToCompare.Where(x=>!ListSource.Contains(x))
                                .Concat(ListSource).OrderBy(x => x).ToArray();

点击此处查看结果：http://ideone.com/6CY4lp

它将保留示例结果中的双16

Answer 2

//Here   is a sample on  how you can achieve this  

 static void Main(string[] args)
    {
       //Two list [source , compare ]
    int[] ListSource = new int[]{ 4,8,12,20,24,32 } ;
    int[] ListToCompare = new int[] { 3, 8, 16, 16, 20, 24, 28, 32,36 };


        var res = ListToCompare.Except(ListSource);
        var NewListSource = ListSource.ToList();
        NewListSource.AddRange(res);
       ListSource = NewListSource.OrderBy(x=>x).ToArray();  




        //And finally my Listsou
    }
}

Answer 3

var set = new HashSet<int>();
set.UnionWith(ListSource);
set.UnionWith(ListToCompare);
ListSource = set.OrderBy(x => x).ToArray();

Answer 4

你可以试试这个：

var except = list2.Except(list1);
var result = list1.Union(except).OrderBy(x => x);

或短

var result = list1.Union(list2.Except(list1)).OrderBy(x => x);

如何比较两个int []数组进行更新和合并的区别？

4 个答案: