Question

我有以下查询我在具有800,000条记录的数据库上运行，但加载时间超过20秒。我在所有列上都有索引，任何人都可以提出更好的查询格式，以便在1.秒下加载这些结果吗？

SELECT SQL_CALC_FOUND_ROWS st.location_limit 
                         , u.user_id
                         , IF(listing_type = 'Company', company, last_name) name 
                      FROM users_data u
                      JOIN subscription_types st
                        ON st.subscription_id = u.subscription_id 
                     WHERE u.active = 2 
                       AND st.searchable = 1  
                     GROUP 
                        BY u.user_id 
                     ORDER 
                        BY st.search_priority ASC 
                     LIMIT 10;

这是我的解释

id  select_type  table               partitions  type  possible_keys                                    key                  key_len  ref                                                       rows    Extra
1   SIMPLE       subscription_types  NULL        ALL   PRIMARY,searchable,id_searchable,search_results  NULL                 NULL     NULL                                                      4       Using where; Using temporary; Using filesort
1   SIMPLE       users_data          NULL        ref   subscription_id,active,subscription_active       subscription_active  8        findades_anti315.subscription_types.subscription_id,const 209261

整个查询就在这里这是整个查询。谢谢。

SELECT SQL_CALC_FOUND_ROWS subscription_types.location_limit as location_limit，users_data.user_id，users_data.last_name，users_data.filename，users_data.user_id，users_data.phone_number，users_data.city，users_data.state_code，users_data.zip_code，users_data.country_code，users_data.quote ，users_data.subscription_id，users_data.company，users_data.position，users_data.profession_id，users_data.experience，users_data.account_type，users_data.verified，users_data.nationwide，IF（listing_type ='Company'，company，last_name）as name FROM {{ 1}} LEFT JOIN users_data ON users_data.user_id = users_reviews.user_id AND users_reviews.review_status ='2'LEFT JOIN users_locations ON users_locations.user_id = users_data.user_id LEFT JOIN subscription_types ON users_data.subscription_id = subscription_types.subscription_id LEFT JOIN users_reviews ON rel_services.user_id = users_data.user_id WHERE users_data.active ='2'AND subscription_types.searchable ='1'AND（（rel_services.service_id ='1383'或rel_services.service_id ='1384'OR rel_serv ices.service_id ='1385'）OR subscription_types.service_limit ='all'）ORDER BY subscription_types.search_priority ASC

优化Mysql左连接800,000+行

0 个答案: