默认函数参数作为初始化结构C ++

Question

如何创建默认函数参数作为具有初始化成员的结构？

#if defined(MIDL_PASS)
typedef struct _LARGE_INTEGER {
#else // MIDL_PASS
typedef union _LARGE_INTEGER {
    struct {
        DWORD LowPart;
        LONG HighPart;
    } DUMMYSTRUCTNAME;
    struct {
        DWORD LowPart;
        LONG HighPart;
    } u;
#endif //MIDL_PASS
    LONGLONG QuadPart;
} LARGE_INTEGER;

LARGE_INTEGER g_l;

void journal(void *foo, const int bar, const LARGE_INTEGER& offsetToHistory = g_l )
{
   return;
}


int main()
{
   g_l.QuadPart = 0;
   LARGE_INTEGER li;
   li.QuadPart = 0;
   journal(NULL, 15, const_cast<LARGE_INTEGER&>(li));
   //I want this the below line to work as well the above.
   //journal(NULL, 15);
}

如何在不使用全局变量“g_l”的情况下实现此目的。实际上，它在构造函数原型中使用，因此我们不能使用全局变量。 我也不想重载构造函数。