试图使用sql获得单行结果？

Question

我正在尝试显示所有员工ID

我需要像

这样的结果

emp_id

10,11,12,13,14,15..,...

尝试时

  

SELECT LISTAGG(emp_id, ',') WITHIN GROUP (ORDER BY emp_id) AS ID FROM employees GROUP BY emp_id;

我收到错误

  

ORA-00923: FROM keyword not found where expected

这里的问题在哪里？

Answer 1

使用LISTAGG功能。有关详细信息，请参阅here。试试这样，

SELECT listagg(emp_id,',') WITHIN GROUP(ORDER BY emp_id) t 
FROM   employees;

Answer 2

试试这个

SELECT CONCAT(emp_id,',') FROM employees;

Answer 3

试试这个

 declare @empid nvarchar(500)=''
    select @empid=@empid+Emp_id + ',' from tblemployee
    select substring(@empid,0,len(@empid)-1)

Answer 4

对于SQL，请尝试

 SELECT GROUP_CONCAT(emp_id) as emp_id FROM employees;

http://sqlfiddle.com/#!2/90dd2/1

的工作演示

对于Oracle

SELECT LISTAGG(emp_id,',') WITHIN GROUP(ORDER BY emp_id) as emp_id 
FROM   employees;

演示http://sqlfiddle.com/#!4/af004/9

Answer 5

试试这个：

SELECT GROUP_CONCAT(emp_id) as emp_id FROM employees;