Question

我正在构建一个网页，用户可以在其中“签署”某些协议并查看签名和新的（未签名）协议。为此，网页使用下面代码中的2个函数从数据库中获取相关信息，然后构建网页。不幸的是，当 - 并且仅当 - php文件（process.php）返回变量nrofagreements = 0时，控制台显示get函数的错误;对于任何其他值nrofagreements＆gt; 0没有错误发生 - 请参阅下面的控制台日志。我还检查了（使用Netbeans调试器）process.php正常工作 - 请参阅下面的json输出nrofagreements = 0-但我仍然怀疑错误必须在这个php文件中（？）任何想法出了什么问题以及如何解决它？

A1。 jquery代码：

$(document).ready(function(){

function NewAgreements(){

var jqxhr = $.get( "process.php", //get all
       { command: "getnewagreements", val1: "", val2: "" },
       function(msg) {

        }, 
        "json"
        ).done(function(msg) {
            console.log( "NewAgreement. $.get result: second success" );
           //some code here to build the form based on msg from $.get()
            form = buildNewAgreementsform(msg); //build form with supplier agreements and related products 
            $("#wrapper").append(form);

            })//.done(function()
        .fail(function() {
            console.log( "NewAgreement. $.get result: error" );
        })//.fail(function()
        .always(function() {
            console.log( "NewAgreement. $.get result: finished" );
       });//$.get( 

}//function getX()
//used by: tabs-agreements

NewAgreements();

function SignedAgreements(){
var jqxhr = $.get( "process.php", //get all
       { command: "getsignedagreements", val1: "", val2: "" },
       function(msg) {
           //var ecorp_eprodselectid;

        }, 
        "json"
      ).done(function(msg) {
            console.log( "SignedAgreement. $.get result: second success" );

            //some code to build the form based on the msg info from $.get()
            form = buildSignedAgreementsform(msg); //build form with supplier agreements and related products 
            $("#wrapper-signedagreements").append(form);

            })//.done(function()
        .fail(function() {
            console.log( "SignedAgreement. $.get result: error" );
        })//.fail(function()
        .always(function() {
            console.log( "SignedAgreement. $.get result: finished" );
       });//$.get( ", 
}

SignedAgreements();

}); //$(document).ready

A2简化的PHP代码：

session_start();

$response_array = array();

$cmd = $_GET['command'];

switch($cmd){     //command handler
case 'getsignedagreements': 
//some code here
$response_array['nrofagreements'] = $k;
    if($response_array['nrofagreements'] == 0){
        $response_array['status_general'] = 'success';
        break;
    }
//some code here
break;

case 'getsignedagreements':
//some code here
break;

default: //invalid command from webpage
    $response_array['status_general'] = 'error';
 break;//default
}//switch

$str = json_encode($response_array);
echo json_encode($response_array);

B中。日志控制台：

NewAgreement. $.get result: error
NewAgreement. $.get result: finished
SignedAgreement. $.get result: second success
SignedAgreement. $.get result: finished

函数NewAgreements的C log json输出：

"{"nrofagreements":0,"status_general":"success"}"

Answer 1

我没有针对你的具体方法，但我有一些能帮助你指明正确方向的东西......

系统设计

我们所珍视的一个理念是，所有事情都需要以最有效的方式做自己的工作。大多数开发人员面临的问题是，他们对应用程序的每个部分将会做什么感到困惑，因此尝试＆amp;用一个组件做5个工作

我之所以解释这个问题是因为您的部分问题是否应该使用JS或PHP进行验证。答案是你必须知道系统的哪个部分会做 - 看起来你正在使用PHP来验证输入是否对会话有效，所以我建议你只处理那个部分的逻辑。 PHP文件

<强>的Ajax

就个人而言，我会在你的$.get命令中处理响应，但我会改为Ajax作为我自己的偏好：

$.ajax({
    url: "process.php",
    data: { command: "getnewagreements", val1: "", val2: "" },
    success: function (msg) {
      //handle validation in here
    },
    error: function(msg) {
        //only fires when the URL can't be found etc
    }
});

Answer 2

我测试了你的代码，在process.php中发现了一个不合逻辑的项目（处理了一个案例）：

//...
case 'getsignedagreements': 
//...

//...
case 'getsignedagreements':
//...

==＆gt; 应更正为（处理两种情况）：

//...
case 'getnewagreements': 
//...

//...
case 'getsignedagreements':
//...

$ .get错误取决于php文件的结果

2 个答案: