Question

我想在用户点按应用程序中的按钮时向Twitter发布推文。我不想使用TWTweetComposeViewController，以便用户再次点击“发送”按钮。我想点击应用程序内的按钮发布推文。（使用iOS Twitter Framework）

有没有办法做到这一点？

由于

Answer 1

使用以下代码执行发布图片和文本而不显示ViewContoller。这称为无声邮政。

 - (void) shareOnTwitterWithMessage:(NSString *)message {

        ACAccountStore *twitterAccountStore = [[ACAccountStore alloc]init];
        ACAccountType *TWaccountType= [twitterAccountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];

        [twitterAccountStore requestAccessToAccountsWithType:TWaccountType options:nil completion:

         ^(BOOL granted, NSError *e) {

             if (granted) {

                 NSArray *accounts = [twitterAccountStore accountsWithAccountType:TWaccountType];

                 twitterAccounts = [accounts lastObject];

                  NSDictionary *dataDict = @{@"status": message};

                 [self performSelectorInBackground:@selector(postToTwitter:) withObject:dataDict];

             }
             else {

                 return ;
             }

         }];
    }


    - (void)postToTwitter:(NSDictionary *)dataDict{

        NSURL *requestURL = [NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/update_with_media.json"];

        SLRequest *request = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:requestURL parameters:dataDict];

        NSData *imageData = UIImagePNGRepresentation([UIImage imageNamed:@"icon@2x.png"]);

        [request addMultipartData:imageData
                         withName:@"media[]"
                             type:@"image/jpeg"
                         filename:@"image.jpg"];

        request.account = twitterAccounts;

        [request performRequestWithHandler:^(NSData *data, NSHTTPURLResponse *response, NSError *error) {

            if(!error){

                NSDictionary *list =[NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];

                if(![list objectForKey:@"errors"]){

                    if([list objectForKey:@"error"]!=nil){

                        //Delegate For Fail
                        return ;
                    }

                }
            }

        }];

    }

Answer 2

试试这个：

NSString *statusesShowEndpoint = @"https://api.twitter.com/1.1/statuses/update.json";
NSDictionary *params = @{@"status": @"Hello, my first autopost tweet..."};

    NSError *clientError;
    NSURLRequest *request = [[[Twitter sharedInstance] APIClient]
                             URLRequestWithMethod:@"POST"
                             URL:statusesShowEndpoint
                             parameters:params
                             error:&clientError];

    if (request) {
        [[[Twitter sharedInstance] APIClient]
         sendTwitterRequest:request
         completion:^(NSURLResponse *response,
                      NSData  *data,
                      NSError *connectionError) {
             if (data) {
                 // handle the response data e.g.
                 NSError *jsonError;
                 NSDictionary *dicResponse = [NSJSONSerialization
                                               JSONObjectWithData:data
                                               options:0
                                               error:&jsonError];
                 NSLog(@"%@",[dicResponse description]);
             }
             else {
                 NSLog(@"Error code: %ld | Error description: %@", (long)[connectionError code], [connectionError localizedDescription]);
             }
         }];
    }
    else {
        NSLog(@"Error: %@", clientError);
    }

使用Twitter框架从iOS应用程序自动发送推文 - 不使用TWTweetComposeViewController

2 个答案: