我正在使用以下代码通过推特分享内容(来自UITextView
,UIImageView
)
-(void)shareViaTweet:(NSString *)shareMessage{
if ([SLComposeViewController isAvailableForServiceType:SLServiceTypeTwitter])
{
SLComposeViewController *tweetSheet = [SLComposeViewController composeViewControllerForServiceType:SLServiceTypeTwitter];
[tweetSheet setInitialText:[NSString stringWithFormat:@"%@",shareMessage]];
if (self.imageString)
{
[tweetSheet addImage:[UIImage imageNamed:self.imageString]];
}
if (self.urlString)
{
[tweetSheet addURL:[NSURL URLWithString:self.urlString]];
}
[self presentViewController:tweetSheet animated:YES completion:nil];
}
else
{
UIAlertView *alertView = [[UIAlertView alloc]
initWithTitle:@"Sorry"
message:@"You can't send a tweet right now, make sure your device has an internet connection and you have at least one Twitter account setup"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertView show];
}
}
但我需要分享这个,而不使用弹出视图(我认为推文表)。它正在发生,因为下面的代码,
[self presentViewController:tweetSheet animated:YES completion:nil];
当我点击我的应用程序的“分享”按钮时,我需要在Twitter上发布。
编辑:
- (IBAction)doneButtonClicked:(id)sender
{
ACAccountStore *account = [[ACAccountStore alloc] init];
ACAccountType *accountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
NSString *message = messageTextView.text;
//hear before posting u can allow user to select the account
NSArray *arrayOfAccons = [account accountsWithAccountType:accountType];
for(ACAccount *acc in arrayOfAccons)
{
NSLog(@"%@",acc.username); //in this u can get all accounts user names provide some UI for user to select,such as UITableview
}
NSURL *url = [NSURL URLWithString:@"https://api.twitter.com"
@"/1.1/statuses/user_timeline.json"];
NSDictionary *params = @{@"screen_name" : message,
@"forKey":@"status",
@"trim_user" : @"1",
@"count" : @"1"};
// Request access from the user to access their Twitter account
[account requestAccessToAccountsWithType:accountType options:nil completion:^(BOOL granted, NSError *error)
{
if (granted == YES)
{
// Populate array with all available Twitter accounts
NSArray *arrayOfAccounts = [account accountsWithAccountType:accountType];
if ([arrayOfAccounts count] > 0)
{
//use the first account available
ACAccount *acct = [arrayOfAccounts objectAtIndex:0]; //hear this line replace with selected account. than post it :)
SLRequest *request =
[SLRequest requestForServiceType:SLServiceTypeTwitter
requestMethod:SLRequestMethodPOST
URL:url
parameters:params];
//Post the request
[request setAccount:acct];
//manage the response
[request performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error)
{
if(error)
{
//if there is an error while posting the tweet
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Twitter" message:@"Error in posting" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
else
{
// on successful posting the tweet
NSLog(@"Twitter response, HTTP response: %i", [urlResponse statusCode]);
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Twitter" message:@"Successfully posted" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
}];
}
else
{
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Twitter" message:@"You have no twitter account" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
}
else
{
//suppose user not set any of the accounts
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Twitter" message:@"Permission not granted" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
} ];
//[widgetsHandler closeWidget:nil];
//[self postImage:shareImageView.image withStatus:messageTextView.text];
}
更新:错误
答案 0 :(得分:4)
要发送图片,你需要做这样的事情
[account requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error)
{
if (granted == YES)
{
// Populate array with all available Twitter accounts
NSArray *arrayOfAccounts = [account accountsWithAccountType:accountType];
if ([arrayOfAccounts count] > 0)
{
//use the first account available
ACAccount *acct = [arrayOfAccounts objectAtIndex:0];
//create this request
SLRequest *postRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"https://api.twitter.com"@"/1.1/statuses/update_with_media.json"] parameters: [NSDictionary dictionaryWithObject:message forKey:@"status"]];
UIImage *imageToPost = [UIImage imageNamed:@"image.jpg"];
NSData *imageData = UIImageJPEGRepresentation(imageToPost, 1.0f);//set the compression quality
[postRequest addMultipartData:imageData withName:@"media" type:@"image/jpeg" filename:@"image.jpg"];
//set account and same as above code
....
....
答案 1 :(得分:1)
如果您想在不使用推文表的情况下分享推文,请参阅我的回答,它将在Twitter壁上发布而不使用推文表,请参阅hear并在设备中设置推特账户。希望这有帮助
不幸的是,在iOS 6中不推荐使用类TWRequest
,但我们可以使用社交框架中的SLRequest
这个答案类似于旧答案 我评论了一些我不想要的东西,但如果你想选择使用哪个帐户,那么取消注释评论代码
- (IBAction)doneButtonClicked:(id)sender
{
ACAccountStore *account = [[ACAccountStore alloc] init];
ACAccountType *accountType = [account accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
NSString *message = _textView.text;
// NSArray *arrayOfAccons = [account accountsWithAccountType:accountType];
// for(ACAccount *acc in arrayOfAccons)
// {
// NSLog(@"%@",acc.username);
// NSDictionary *properties = [acc dictionaryWithValuesForKeys:[NSArray arrayWithObject:@"properties"]];
// NSDictionary *details = [properties objectForKey:@"properties"];
// NSLog(@"user name = %@",[details objectForKey:@"fullName"]);
// NSLog(@"user_id = %@",[details objectForKey:@"user_id"]);
// }
// Request access from the user to access their Twitter account
[account requestAccessToAccountsWithType:accountType withCompletionHandler:^(BOOL granted, NSError *error)
{
if (granted == YES)
{
// Populate array with all available Twitter accounts
NSArray *arrayOfAccounts = [account accountsWithAccountType:accountType];
if ([arrayOfAccounts count] > 0)
{
//use the first account available
ACAccount *acct = [arrayOfAccounts objectAtIndex:0];
// Build a twitter request
// TWRequest *postRequest = [[TWRequest alloc] initWithURL:
// [NSURL URLWithString:@"http://api.twitter.com/1/statuses/update.json"] parameters:[NSDictionary dictionaryWithObject:message forKey:@"status"] requestMethod:TWRequestMethodPOST]; //commented the deprecated method of TWRequest class
SLRequest *postRequest = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:[NSURL URLWithString:@"http://api.twitter.com/1/statuses/update.json"] parameters:[NSDictionary dictionaryWithObject:message forKey:@"status"]]; //use this method instead
//Post the request
[postRequest setAccount:acct];//set account
//manage the response
[postRequest performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error)
{
if(error)
{
//if there is an error while posting the tweet
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Twitter" message:@"Error in posting" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
[alert release];
}
else
{
// on successful posting the tweet
NSLog(@"Twitter response, HTTP response: %i", [urlResponse statusCode]);
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Twitter" message:@"Successfully posted" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
[alert release];
}
}];
}
else
{
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Twitter" message:@"You have no twitter account" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
[alert release];
}
}
else
{
//suppose user not set any of the accounts
UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Twitter" message:@"You have no twitter account" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
[alert release];
}
} ];
[account release];
}