我几乎让我的needleman-wunsch实现工作但我对如何处理特定情况下的追溯感到困惑。
我们的想法是，为了重新构建序列（最长路径），我们重新计算以确定得分来自的矩阵。我遇到问题的边缘情况是右下方得分不在匹配矩阵中，但是在插入列矩阵中（意味着得到的跟踪序列应该有插入。
这些序列以a2m格式记录，其中序列中的插入记录为小写字符。因此，在最终输出中，ZZ与AAAC的对齐应为AAac。当我手动追溯时，我最终得到AAAc，因为我只访问过一次Ic矩阵。 Here是我白板的照片。如你所见，我有三个黑色箭头和一个绿色箭头，这就是为什么我的追溯给了我AAAc。我应该计算第一个单元格，然后停在1,1位置？我不确定如何改变我实现它的方式。
请注意，此处使用的替换矩阵是BLOSUM62。重现关系是
M(i,j) = max(Ic(i-1,j-1)+subst, M(i-1,j-1)+subst, Ir(i-1,j-1)+subst)
Ic(i,j) = max(Ic(i,j-1)-extend, M(i,j-1)-open, Ir(i,j-1)-double)
Ir(i,j) = max(Ic(i-1,j)-double, M(i-1,j)-open, Ir(i-1,j)-extend)
编辑：这是traceback_col_seq函数重写为更清洁。请注意，score_cell现在返回thisM，thisC，thisR而不是其中的最大值。这个版本将对齐评为AaAc，仍然存在同样的问题，现在又出现了另一个问题，即为什么它会在1,2处再次进入Ic。但是这个版本更清晰。
def traceback_col_seq(self):
i, j = self.maxI-1, self.maxJ-1
self.traceback = list()
matrixDict = {0:'M',1:'Ic',2:'Ir',3:'M',4:'Ic',5:'Ir',6:'M',7:'Ic',8:'Ir'}
while i > 0 or j > 0:
chars = self.col_seq[j-1] + self.row_seq[i-1]
thisM, thisC, thisR = self.score_cell(i, j, chars)
cell = thisM + thisC + thisR
prevMatrix = matrixDict[cell.index(max(cell))]
print(cell, prevMatrix,i,j)
if prevMatrix == 'M':
i -= 1; j -= 1
self.traceback.append(self.col_seq[j])
elif prevMatrix == 'Ic':
j -= 1
self.traceback.append(self.col_seq[j].lower())
elif prevMatrix == 'Ir':
i -= 1
self.traceback.append('-')
return ''.join(self.traceback[::-1])
这是python类，它生成动态编程矩阵并追溯对齐。还有一个评分函数用于检查产生的对齐是否正确。
class global_aligner():
def __init__(self, subst, open=12, extend=1, double=3):
self.extend, self.open, self.double, self.subst = extend, open, double, subst
def __call__(self, row_seq, col_seq):
#add alphabet error checking?
score_align(row_seq, col_seq)
return traceback_col_seq()
def init_array(self):
"""initialize three numpy arrays, set values in 1st column and row"""
self.M = zeros((self.maxI, self.maxJ), float)
self.Ic = zeros((self.maxI, self.maxJ), float)
self.Ir = zeros((self.maxI, self.maxJ), float)
for i in xrange(1,self.maxI):
self.M[i][0], self.Ic[i][0], self.Ir[i][0] = \
-float('inf'), -float('inf'), -(self.open+self.extend*(i-1))
for j in xrange(1,self.maxJ):
self.M[0][j], self.Ir[0][j], self.Ic[0][j] = \
-float('inf'), -float('inf'), -(self.open+self.extend*(j-1))
self.Ic[0][0] = self.Ir[0][0] = -float('inf')
def score_cell(self, i, j, chars):
"""score a matrix cell based on the 9 total neighbors (3 each direction)"""
thisM = [self.M[i-1][j-1]+self.subst[chars], self.Ic[i-1][j-1]+ \
self.subst[chars], self.Ir[i-1][j-1]+self.subst[chars]]
thisC = [self.M[i][j-1]-self.open, self.Ic[i][j-1]-self.extend, \
self.Ir[i][j-1]-self.double]
thisR = [self.M[i-1][j]-self.open, self.Ic[i-1][j]-self.double, \
self.Ir[i-1][j]-self.extend]
return max(thisM), max(thisC), max(thisR)
def score_align(self, row_seq, col_seq):
"""build dynamic programming matrices to align two sequences"""
self.row_seq, self.col_seq = list(row_seq), list(col_seq)
self.maxI, self.maxJ = len(self.row_seq)+1, len(self.col_seq)+1
self.init_array() #initialize arrays
for i in xrange(1, self.maxI):
row_char = self.row_seq[i-1]
for j in xrange(1, self.maxJ):
chars = row_char+self.col_seq[j-1]
self.M[i][j], self.Ic[i][j], self.Ir[i][j] = self.score_cell(i, j, chars)
def traceback_col_seq(self):
"""trace back column sequence in matrices in a2m format"""
i, j = self.maxI-1, self.maxJ-1
self.traceback = list()
#find which matrix to start in
#THIS IS WHERE THE PROBLEM LIES I THINK
cell = (self.M[i][j], self.Ic[i][j], self.Ir[i][j])
prevMatrix = cell.index(max(cell))
while i > 1 and j > 1:
if prevMatrix == 0: #M matrix
i -= 1; j -= 1 #step up diagonally
prevChars = self.row_seq[i-1]+self.col_seq[j-1]
diag = self.score_cell(i, j, prevChars) #re-score diagonal cell
prevMatrix = diag.index(max(diag)) #determine which matrix that was
self.traceback.append(self.col_seq[j])
elif prevMatrix == 1: #Ic matrix
j -= 1
prevChars = self.row_seq[i-1]+self.col_seq[j-1]
left = self.score_cell(i, j, prevChars)
prevMatrix = left.index(max(left))
self.traceback.append(self.col_seq[j].lower())
elif prevMatrix == 2: #Ir matrix
i -= 1
prevChars = self.row_seq[i-1]+self.col_seq[j-1]
up = self.score_cell(i, j, prevChars)
prevMatrix = up.index(max(up))
self.traceback.append('-')
for j in xrange(j,0,-1): #hit top of matrix before ending, add chars
self.traceback.append(self.col_seq[j-1])
for i in xrange(i,0,-1): #hit left of matrix before ending, add gaps
self.traceback.append('-')
print(''.join(self.row[::-1]))
return ''.join(self.traceback[::-1])
def score_a2m(self, s1, s2):
"""scores an a2m alignment of two sequences. I believe this function correctly
scores alignments and is used to test my alignments. The value produced by this
function should be the same as the largest value in the bottom right of the three
matrices"""
s1, s2 = list(s1.strip('.')), list(s2.strip('.'))
s1_pos, s2_pos = len(s1)-1, len(s2)-1
score, gap = 0, False
while s1_pos >= 0 and s2_pos >= 0:
if s1[s1_pos].islower() and gap is False:
score -= self.open; s1_pos -= 1; gap = True
elif s1[s1_pos].islower() and gap is True:
score -= self.extend; s1_pos -= 1
elif s2[s2_pos].islower() and gap is False:
score -= self.open; s2_pos -= 1; gap = True
elif s2[s2_pos].islower() and gap is True:
score -= self.extend; s2_pos -= 1
elif s1[s1_pos] == '-' and gap is False:
score -= self.open; s1_pos -= 1; s2_pos -= 1; gap = True
elif s1[s1_pos] == '-' and gap is True:
score -= self.extend; s1_pos -= 1; s2_pos -= 1
elif s2[s2_pos] == '-' and gap is False:
score -= self.open; s1_pos -= 1; s2_pos -= 1; gap = True
elif s2[s2_pos] == '-' and gap is True:
score -= self.extend; s1_pos -= 1; s2_pos -= 1
elif gap is True:
score += self.subst[s1[s1_pos].upper() + s2[s2_pos].upper()]
s1_pos -= 1; s2_pos -= 1; gap = False
else:
score += self.subst[s1[s1_pos].upper() + s2[s2_pos].upper()]
s1_pos -= 1; s2_pos -= 1
if s1_pos >= 0 and gap is True:
score -= self.extend*s1_pos
elif s1_pos >= 0 and gap is False:
score -= self.open+s1_pos*self.extend
if s2_pos >= 0 and gap is True:
score -= self.extend*s2_pos
elif s2_pos >= 0 and gap is False:
score -= self.open+s2_pos*self.extend
return score
test = global_aligner(blosumMatrix)
s1,s2 = 'ZZ','AAAC'
test.score_align(s1, s2)
align = test.traceback_col_seq()
print('This score: ', test.score_a2m(s1,align)
print('Correct score: ', test.score_a2m(s1,'AAac'))
Blosum解析器
def parse_blosum(blosumFile):
blosumMatrix, commentFlag = dict(), False
for line in blosumFile:
if not line.startswith('#') and not commentFlag:
alphabet = line.rstrip().split()
commentFlag = True
elif commentFlag:
line = line.rstrip().split()
thisChar, line = line[0], line[1:]
for x in xrange(len(line)):
alphaChar, thisValue = alphabet[x], line[x]
blosumMatrix[thisChar+alphaChar] = int(thisValue)
return blosumMatrix
答案 0 :(得分：4)
def traceback_col_seq(self):
"""
Traces back the column sequence to determine final global alignment.
Recalculates the score using score_cell.
"""
i, j = self.maxI-1, self.maxJ-1
self.traceback = list() #stores final sequence
matrixDict = {0:'M',1:'Ic',2:'Ir'} #mapping between numeric value and matrix
chars = self.col_seq[j-1] + self.row_seq[i-1] #store first characters
thisM, thisC, thisR = self.score_cell(i,j, chars)
cell = max(thisM), max(thisC), max(thisR) #determine where to start
prevMatrix = matrixDict[cell.index(max(cell))] #store where to go first
while i > 0 or j > 0:
#loop until the top left corner of the matrix is reached
if prevMatrix == 'M':
self.traceback.append(self.col_seq[j-1])
i -= 1; j -= 1
prevMatrix = matrixDict[thisM.index(max(thisM))]
elif prevMatrix == 'Ic':
self.traceback.append(self.col_seq[j-1].lower())
j -= 1
prevMatrix = matrixDict[thisC.index(max(thisC))]
elif prevMatrix == 'Ir':
self.traceback.append('-')
i -= 1
prevMatrix = matrixDict[thisR.index(max(thisR))]
chars = self.col_seq[j-1] + self.row_seq[i-1] #store next characters
thisM, thisC, thisR = self.score_cell(i,j, chars) #rescore next cell
return ''.join(self.traceback[::-1])
答案 1 :(得分：2)
正如您提到的关于箭头颜色的评论，基本问题是第二个水平箭头被标记为M（黑色箭头）中的移动，当它实际上是Ic（绿色箭头）中的移动时。这似乎正在发生，因为prevMatrix变量指示（i-1，j-1），（i-1，j）或（i，j-1）处的最佳矩阵。这是前向视角中前一个单元格中的矩阵。由于此时你正在做跟踪*返回*，你在跟踪中“来自”的单元格实际上是（i，j） - 你当前所在的单元格。这决定了你移动的方向和因此，无论你是否正在调整差距。你最好的选择可能是有一个变量来跟踪从循环迭代到循环迭代的当前矩阵，并使用它来确定要附加到对齐字符串的字符。在每次迭代后，您可以在确定下一个要访问的单元格后更新它。
我认为进行这些更改将澄清您重新编写的traceback_col_sequence函数遇到的问题，但初步看起来您没有考虑通过回溯获得的信息。您正在重复使用score_cell()，它看起来像是为了计算未来的分数而设计的。当您追溯时，您已经知道了结尾，因此您不希望选择前一个单元格的最大分数。您希望选择可能导致您当前所在矩阵中的位置的最大分数。例如，如果你知道回溯中的矩阵是M，那么你知道你没有通过扩大差距来实现这一目标，所以你不应该考虑这些选项。