Question

我有两张桌子：

create table saller(
id_saller int IDENTITY  PRIMARY KEY,
name varchar(50), 
branch varchar(10)
);

create table sale(
id_sale int IDENTITY PRIMARY KEY,
amount float,
id_saller int,
CONSTRAINT fk_saller  FOREIGN KEY (id_saller)REFERENCES saller(id_saller)
);

我想获得每个分支的最大销售价值并获得负责最畅销的卖方的名称和身份

我试过这个：

SELECT saller.name, saller.id_saller,maxv.branch, maxv.maxbranch
FROM saller 
INNER JOIN sale
 ON  saller.id_saller = sale.id_saller 
INNER JOIN (
    SELECT saller.branch,saller.id_saller,MAX(sale.amount) AS maxbranch
    FROM  saller
    INNER JOIN sale 
        ON saller.id_saller = sale.id_saller 
    GROUP BY saller.branch,saller.id_saller
) AS maxv ON(sale.id_saller = maxv.id_saller)

Answer 1

根据你的问题，我不明白分支的存在，也许是一个没有提及的表格。但要检索卖家ID和名称，您可以试试这个;

SELECT saller.name, saller.id_saller 
FROM   saller 
INNER JOIN sale 
  ON  saller.id_saller = sale.id_saller 
WHERE sale.Amount = (Select Max(Amount) from sale)

Answer 2

如果你想要为每个分支返回一行，即使你有联系

，也可以采用这种方法

SELECT branch, id_saller, name, amount
  FROM
(
  SELECT r.branch, s.id_saller, r.name, s.amount, 
         ROW_NUMBER() OVER (PARTITION BY r.branch ORDER BY s.amount DESC) rnum
    FROM sale s JOIN saller r
      ON s.id_saller = r.id_saller
) q
 WHERE q.rnum = 1

或者如果你想要带有关系的最高值

SELECT branch, id_saller, name,  amount
  FROM
(
  SELECT r.branch, s.id_saller, r.name, s.amount, 
         RANK() OVER (PARTITION BY r.branch ORDER BY s.amount DESC) rank
    FROM sale s JOIN saller r
      ON s.id_saller = r.id_saller
) q
 WHERE q.rank = 1

这是 SQLFiddle 演示

获取列的每个最大值并从另一个表中获取信息

2 个答案: