Question

我想要datetime

这两个1day , 2hours, 3min.列的差异

我试过这个，

DECLARE @end datetime2 = '2013-11-13 09:35:49.007'
DECLARE @start datetime2 =  '2013-11-12 17:34:11.533'

select datediff(day, @start, @end) days,
datediff(HOUR, @start, @end) Hours,
datediff(MINUTE, @start, @end) Minutes

输出

1day    16hours 961minutes.

但我想要输出1day 4hours 30min.

需要一些帮助来解决这个问题。谢谢

Answer 1

样品的差异是16小时，1分钟和38秒。你在哪里提出1天，4小时30分钟？ 17:34是下午5:34，而不是早上5:34。

这是从日期差异中执行描述性文本的代码。注意：要解决0周，天，小时等的边缘情况，您必须在进行演员表之前进行检查。

DECLARE @end datetime2 = '2013-11-13 09:35:49.007'
DECLARE @start datetime2 =  '2013-11-12 17:34:11.533'

SELECT ''
    +  CAST(DATEDIFF(second, @start, @end) / 60 / 60 / 24 / 7 AS NVARCHAR(50)) + ' weeks, '
    + CAST(DATEDIFF(second, @start, @end) / 60 / 60 / 24 % 7 AS NVARCHAR(50)) + ' days, '
    + CAST(DATEDIFF(second, @start, @end) / 60 / 60 % 24  AS NVARCHAR(50)) + ' hours, '
    + CAST(DATEDIFF(second, @start, @end) / 60 % 60 AS NVARCHAR(50)) + ' minutes and '
    + CAST(DATEDIFF(second, @start, @end) % 60 AS NVARCHAR(50)) + ' seconds.';

<强>输出：

0 weeks, 0 days, 16 hours, 1 minutes and 38 seconds.

得到日期时间差为1天，2小时，30分钟

1 个答案: