Question

我试图获得两个属性总和（带有权重）并最终将它们组合成一个组合权重。

因此，首先是单独的查询，因此您可以看到正确的总和权重

Language = French，熟练程度超过6（1-10级）：

MATCH (User)-[Speaks]->(Language) 
WHERE Language.language = 'French' AND Speaks.proficiency >=6 
RETURN User.name, SUM(
CASE
    WHEN Language.language='French'  THEN Speaks.proficiency*3  
    END )*0.1 AS TOTAL_Language
ORDER BY TOTAL_Language DESC

User.name TOTAL_Language 大卫3 Marion 1.8

Skill = Finance,Banking,IT,Marketing Weight =1 (of 1)：

MATCH (User)-[IsSkilledIn]->(Skill)
WHERE  Skill.skill IN ['Finance','Banking','IT','Marketing']
RETURN User.name, SUM(
CASE
    WHEN Skill.skill='Finance' THEN IsSkilledIn.weight*10
    WHEN Skill.skill='Banking' THEN IsSkilledIn.weight*5        
    WHEN Skill.skill='IT' THEN IsSkilledIn.weight*8
WHEN Skill.skill='Marketing' THEN IsSkilledIn.weight*1
END )*0.1 AS TOTAL_Skill
ORDER BY TOTAL_Skill DESC

User.name   TOTAL_Skill
Eric            1.5
Marion          0.9
David           0.8
Hans            0.8

所以现在，我尝试将这些查询组合成：

French >=6 AND Skills Finance,Banking,IT,Marketing：

MATCH (User)-[Speaks]->(Language) , (User)-[IsSkilledIn]->(Skill)
WHERE Language.language = 'French' AND Speaks.proficiency >=6 AND Skill.skill IN ['Finance','Banking','IT','Marketing']
RETURN User.name, SUM(
CASE
    WHEN Language.language='French'  THEN Speaks.proficiency*3   
    END )*0.1 AS TOTAL_Language,
SUM(
CASE
    WHEN Skill.skill='Finance' THEN IsSkilledIn.weight*10
    WHEN Skill.skill='Banking' THEN IsSkilledIn.weight*5        
    WHEN Skill.skill='IT' THEN IsSkilledIn.weight*8
    WHEN Skill.skill='Marketing' THEN IsSkilledIn.weight*1
END )*0.1 AS TOTAL_Skill
ORDER BY TOTAL_Skill DESC

现在我得到了这些结果：

 User.name  TOTAL_Language  TOTAL_Skill
 Marion          3.6            0.9
 David       3                  0.8

马里昂的TOTAL_Language是第一个答案的两倍。

所以我检查了什么可能是错的，它必须在WHERE-Clause中，但我不知道什么是错的。

我怎样才能总结两个结果？

Answer 1

啊，我看到了问题。你最终得到两个结果而不是一个结果，因为你的匹配匹配两个技能记录。您需要做的是将两个查询放在一起，因此总和将单独计算。

MATCH (User)-[Speaks]->(Language) 
WHERE Language.language = 'French' AND Speaks.proficiency >=6 
WITH User, SUM(
CASE
    WHEN Language.language='French'  THEN Speaks.proficiency*3  
    END )*0.1 AS TOTAL_Language
MATCH (User)-[IsSkilledIn]->(Skill)
WHERE  Skill.skill IN ['Finance','Banking','IT','Marketing']
RETURN User.name, TOTAL_Language, SUM(
CASE
    WHEN Skill.skill='Finance' THEN IsSkilledIn.weight*10
    WHEN Skill.skill='Banking' THEN IsSkilledIn.weight*5        
    WHEN Skill.skill='IT' THEN IsSkilledIn.weight*8
    WHEN Skill.skill='Marketing' THEN IsSkilledIn.weight*1
END )*0.1 AS TOTAL_Skill
ORDER BY TOTAL_Skill DESC

Answer 2

另一个选择是仍然使用一个查询，但收集一个人的技能，并总结技能权重的集合，而不是对行进行求和，

MATCH (User)-[Speaks]->(Language), (User)-[IsSkilledIn]->(Skill) 
WHERE Language.language = 'French' 
 AND Speaks.proficiency >=6 
 AND Skill.skill IN ['Finance','Banking','IT','Marketing']
WITH User.name as userName, 
     (CASE WHEN Language.language='French' 
           THEN Speaks.proficiency*3 END) as languageProficiency, 
      collect(CASE 
              WHEN Skill.skill='Finance' THEN IsSkilledIn.weight*10 
              WHEN Skill.skill='Banking' THEN IsSkilledIn.weight*5 
              WHEN Skill.skill='IT' THEN IsSkilledIn.weight*8 
              WHEN Skill.skill='Marketing' THEN IsSkilledIn.weight*1 
              END) as skillWeightCollection
RETURN userName, 
       sum(languageProficiency)*0.1 as TOTAL_Language, 
       reduce(totalSkill = 0, skillWeight in skillWeightCollection | 
              totalSkill + skillWeight) * 0.1 as TOTAL_SKILL

如何总结不同的物业权重？

2 个答案: