Question

我有以下情况：当用户点击时，我需要一次上传3个文件。我的观点中有代码：

<?php echo form_open_multipart('uploads/do_upload', 'class="dropzone", id="dropzone-prod", data-nextFormExecDropzone="#dropzone-promo"');?>
   <div class="fallback">
     <input type="file" name="userfile" size="20" />
   </div>
</form>
<?php echo form_open_multipart('uploads/do_upload', 'class="dropzone", id="dropzone-promo", data-nextFormExecDropzone="#dropzone-plan"');?>
   <div class="fallback">
     <input type="file" name="userfile" size="20" />
   </div>
</form>
<?php echo form_open_multipart('uploads/do_upload', 'class="dropzone", id="dropzone-plan"');?>
   <div class="fallback">
     <input type="file" name="userfile" size="20" />
   </div>
</form>
<div class="col-lg-4">
    <button id="processQueue"  class="btn btn-primary" type="button"><i class="fa fa-upload"></i>Start Upload</button>
</div>

当用户点击按钮时，我有一个javascript代码，可以按照我想要的顺序发送每个表单。在我的控制器中，我有以下方法（do_upload（））：

function do_upload() {
    //$filePath = $this->config->item('base_current_upload_url');
    $filePath = APPPATH.'UPLOADS/';
    $filePathAfterUploaded = $this->config->item('base_uploaded_url');

    $config['upload_path'] = $filePath;
    $config['allowed_types'] = '*';
    $config['max_size'] = 1024 * 100;

    $this->load->library('upload', $config);

    //$this->load->library('csvreader');
    //$filePathAfterUploaded = $this->config->item('base_uploaded_url');
    //print_r($filePath); die();
    $basefilepath = APPPATH.'UPLOADS/';
    $this->load->model('uploads_m');

    if ( ! $this->upload->do_upload('file')) {
        $error = array('error' => $this->upload->display_errors());

        print_r($error);
    }
    else {
        $data = array('upload_data' => $this->upload->data());
        print_r($data); die();
    }

}

问题：

我需要上传3个文件。如果只有一个丢失，我无法继续。我正在这样做，在上传每个文件的过程中调用do_upload函数，所以我需要找到一种方法来识别上传的3个文件。（之后，我将使用mysql'load data infile'将这些文件中的数据加载到某些表中，但我只能在上传三个表时执行此操作。你能帮我找到解决这种情况的方法吗？

每次调用do_uplaod时$ data的结构是：

Array
(
[upload_data] => Array
    (
        [file_name] => PROMOWEB111120131.txt
        [file_type] => text/plain
        [file_path] => C:/Program Files/EasyPHP-DevServer-13.1VC9/data/localweb/projects/integration/www/application/UPLOADS/
        [full_path] => C:/Program Files/EasyPHP-DevServer-13.1VC9/data/localweb/projects/integration/www/application/UPLOADS/PROMOWEB111120131.txt
        [raw_name] => PROMOWEB111120131
        [orig_name] => PROMOWEB11112013.txt
        [client_name] => PROMOWEB11112013.txt
        [file_ext] => .txt
        [file_size] => 2.67
        [is_image] => 
        [image_width] => 
        [image_height] => 
        [image_type] => 
        [image_size_str] => 
    )

)

Answer 1

如果do_upload是一个独立的函数，那么引入一个计算调用次数的静态变量。

function do_upload () {
    static $count = 0;
    // The rest of your function goes here
    if (no_errors_occurred) {
        static::$count++;
    }
    if ($count == 3) {
        // This function has been called 3 times; trigger something here
    }
}

更好的是，如果它在课堂上......

class MyClass {
    protected static $data = array ();

    // Other functions and properties

    public function do_upload () {
        // The rest of your function
        if (no_errors_occurred) {
            static::$data[] = array (
                'upload_data' => array (
                    'file_name' => ...,
                    // Populate the data array
                )
            );
        }
        $this->do_mysql_load_data_infile();
    }

    protected function do_mysql_load_data_infile () {
        if (count(static::$data) != 3) {
            return false;
        }
        // Do MySQL load data infile
        // Get information about file uploads by accessing the static::$data array
        foreach (static::$data as $file) {
            echo $file['upload_data']['file_name'];
        }
    }
}

将上传的文件数据存储到数组中

1 个答案: