Question

这篇文章是JPA : Not able to persist record due to incorrect values being passed from client to server

的延续

当我从服务器JSON输出中检索值时，格式如下。

   {"emp":[{"dept":{"deptNo":"10","dname":"ACCOUNTING","loc": 
  "NEW YORK"},"empno":"7934","ename":"MILLER","hiredate":
  "1982-01-23T00:00:00+03:00","job":"CLERK","mgr":"7782","sal":"1300"},
  {"dept":
  {"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7902","ename":
  "FORD",
  "hiredate":"1981-12-03T00:00:00+03:00","job":"ANALYST","mgr":"7566","sal":
  "3000"},{"dept": 
  {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7900","ename":
  "JAMES", "hiredate":
  "1981-12-03T00:00:00+03:00","job":"CLERK","mgr":"7698","sal":"950"},
  {"dept":{"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7876",
  "ename":
  "ADAMS","hiredate":
  "1987-05-23T00:00:00+03:00","job":"CLERK","mgr":"7788","sal":"1100"},
  {"comm":"0","dept":      
  {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7844","ename":
  "TURNER","hiredate":
  "1981-09-08T00:00:00+03:00","job":"SALESMAN","mgr":"7698","sal":"1500"},
  {"dept":{"deptNo":"10","dname":"ACCOUNTING","loc":
  "NEW YORK"},"empno":"7839","ename":"KING","hiredate":
  "1981-11-17T00:00:00+03:00","job":"PRESIDENT","sal":"5000"},         
  {"dept":"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7788",
  "ename":"SCOTT","hiredate":
  "1987-04-19T00:00:00+03:00","job":"ANALYST","mgr":"7566","sal":"3000"},
   {"dept":{"deptNo":"10","dname":"ACCOUNTING","loc":
   "NEW YORK"},"empno":"7782","ename":"CLARK","hiredate":
   "1981-06-09T00:00:00+03:00","job":"MANAGER","mgr":"7839","sal":"2450"},
   {"dept":"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7698",
   "ename":
    "BLAKE","hiredate":
   "1981-05-01T00:00:00+03:00","job":"MANAGER","mgr":"7839","sal":"2850"},
   {"comm":"1400","dept": 
   {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7654","ename":
    "MARTIN","hiredate":
   "1981-09-28T00:00:00+03:00","job":"SALESMAN","mgr":"7698","sal":"1250"},
   {"dept":
   {"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7566","ename": 
    "JONES","hiredate":
   "1981-04-02T00:00:00+03:00","job":"MANAGER","mgr":"7839","sal":"2975"},
   {"comm":"500","dept": 
   {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7521","ename":
   "WARD", "hiredate":
   "1981-02-22T00:00:00+03:00","job":"SALESMAN","mgr":"7698","sal":"1250"},
    {"comm":"300","dept":
    {"deptNo":"30","dname":"SALES","loc":"CHICAGO"},"empno":"7499",
   "ename":
   "ALLEN","hiredate":"1981-02-20T00:00:00+03:00","job":"SALESMAN","mgr":
   "7698",
   "sal":"1600"},{"dept":
   {"deptNo":"20","dname":"RESEARCH","loc":"DALLAS"},"empno":"7369","ename":
    "SMITH","hiredate":
   "1980-12-17T00:00:00+03:00","job":"CLERK","mgr":"7902","sal":"800"}]}

如果我想将数据插入到EMP表中，如何预期数据以及如何将数据从客户端JSON传递到服务器？

我尝试了以下格式，但它没有帮助。

function formToJSON() {
      return JSON.stringify({
                    "deptNo": "10",
                    "empno": "9004",
                    "ename": "JILL",
                    "job": "mfg",
                    "mgr": 34,
                    "sal": 456,
                    "comm": 900
                });
            }


$(document).ready(function() {
                $("#btnSubmit").click(function() {
                    $.ajax({
                        url: "Test1/rest/employee/",
                        type: "POST",
                        data: formToJSON(),
                        contentType: "application/json; charset=utf-8",
                        dataType: "json",
                        // console : 'ok',
                    })
                });
            });

当我从浏览器提交时，当我在服务器中收到时，deptNo为零。它在服务器中的预期效果如何？

Answer 1

实际上你向服务器发送了错误的json格式，这就是你得到deptNo = 0的原因。

正确的Json格式是这样的。

{
    "deptNo":{
          "deptNo":500,
          "dname":"RESEARCH",
          "loc":"DALLAS"
       },
       "empno":7876,
       "ename":"ADAMS",
       "job":"1100",
       "sal":"7788"
    }

您可以将json字符串化为

function formToJSON() {

  var test = {  empno:7876, ename:'ADAMS', job:1100, sal:7788,
                 deptNo:{deptNo:6, dname:'RESEARCH', loc:'DALLAS'}
               };

    return JSON.stringify(test);

    }

JPA的续篇：Not able to persist record due to incorrect values being passed from client to server

还有这种json格式问题。

JSON数据转换为Java Object

1 个答案: