我无法将Java对象转换为JSON对象,这是我的主要Java对象:
我这样做:
public class LoginDao {
String company;
String user;
String secure_password;
String secure_device_id;
app_info app_info;
}
jsonObject.put("company", company);
jsonObject.put("user", user);
jsonObject.put("os", os);
jsonObject.put("ver", ver);
jsonObject.put("lang", lang);
但是在输出上我没有这个:
{
"company":"",
"user":"test",
"secure_password":"",
"secure_device_id":"",
"app_info":
{
"os":"soapui",
"ver":1,
"lang":"pl"
}
}
答案 0 :(得分:1)
如果需要以上输出,请尝试以下操作:
JSONObject obj = new JSONObject();
obj.put("company", company);
obj.put("user", user);
obj.put("secure_password", secure_password);
obj.put("secure_device_id", secure_device_id);
JSONObject anothetObj = new JSONObject();
anothetObj.put("os", os);
anothetObj.put("ver", ver);
anothetObj.put("lang", lang);
obj.put("app_info", anothetObj);
答案 1 :(得分:1)
您可以创建两个DAO类,
public class LoginDAO {
private String company;
private String user;
private String secure_password;
private String secure_device_id;
// Getter Methods
public String getCompany() {
return company;
}
public String getUser() {
return user;
}
public String getSecure_password() {
return secure_password;
}
public String getSecure_device_id() {
return secure_device_id;
}
// Setter Methods
public void setCompany( String company ) {
this.company = company;
}
public void setUser( String user ) {
this.user = user;
}
public void setSecure_password( String secure_password ) {
this.secure_password = secure_password;
}
public void setSecure_device_id( String secure_device_id ) {
this.secure_device_id = secure_device_id;
}
}
public class App_info {
private String os;
private float ver;
private String lang;
// Getter Methods
public String getOs() {
return os;
}
public float getVer() {
return ver;
}
public String getLang() {
return lang;
}
// Setter Methods
public void setOs( String os ) {
this.os = os;
}
public void setVer( float ver ) {
this.ver = ver;
}
public void setLang( String lang ) {
this.lang = lang;
}
}
然后您就可以这样做
LoginDAO login = new LoginDAO();
App_info app = new App_info();
JSONObject jo = new JSONObject();
jo.put("company", login.getCompany());
jo.put("user", login.getUser());
jo.put("secure_password", login.getSecure_password());
jo.put("secure_device_id", login.getSecure_device_id());
Map m = new LinkedHashMap(3);
m.put("os", app.getOs());
m.put("ver", app.getVer());
m.put("lang", app.getLang());
jo.put("app_info", m);
System.out.println(jo.toString);
如果没有,您可以简单地做到这一点,
JSONObject jo = new JSONObject(
"{ \"company\":\"\", \"user\":\"test\", \"secure_password\":\"\", \"secure_device_id\":\"\", \"app_info\": { \"os\":\"soapui\", \"ver\":1, \"lang\":\"pl\" } }"
);
答案 2 :(得分:1)
您可以通过更多方式执行此操作。如下所示:
使用Google Gson :
Maven依赖项:
<dependency>
<groupId>com.google.code.gson</groupId>
<artifactId>gson</artifactId>
<version>2.8.0</version>
</dependency>
Java代码:
LoginDao loginData;
// Here loginData is the object. ...
Gson gson = new Gson();
String json = gson.toJson(loginData);
使用Jacson :
等级依赖性:
compile 'com.fasterxml.jackson.core:jackson-databind :2.5.3'
Java代码
ObjectWriter ow = new ObjectMapper().writer().withDefaultPrettyPrinter();
String json = ow.writeValueAsString(loginData);