import pygame, random
from pygame import*
pygame.init()
myname=input('What is your name')
#set the window size
window= pygame.display.set_mode((800,600) ,0,24)
pygame.display.set_caption("Fruit Catch")
#game variables
myscore=0
mylives=3
mouth_x=300
fruit_x=250
fruit_y=75
fruitlist=['broccoli.gif','chicken.gif']
#prepare for screen
myfont=pygame.font.SysFont("Britannic Bold", 55)
label1=myfont.render(myname, 1, (240, 0, 0))
label3=myfont.render(str(mylives), 1, (20, 255, 0))
#grapchics
fruit=pygame.image.load('data/chicken.png')
mouth=pygame.image.load('data/v.gif')
backGr=pygame.image.load('data/kfc.jpg')
#endless loop
running=True
while running:
if fruit_y>=460:#check if at bottom, if so prepare new fruit
fruit_x=random.randrange(50,530,1)
fruit_y=75
fruit=pygame.image.load('data/'+fruitlist[random.randrange(0,2,1)])
caught= fruit_x>=mouth_x and fruit_x<=mouth_x+300
else:fruit_y+=5
#check collision
if fruit_y>=440:
if fruit_x>=mouth_x and fruit_x<=mouth_x+300 :
myscore+=1
fruit_y=600#move it off screen
pygame.mixer.music.load('data/eating.wav')
#detect key events
for event in pygame.event.get():
if (event.type==pygame.KEYDOWN):
if (event.key==pygame.K_LEFT):
mouth_x-=55
if (event.key==pygame.K_RIGHT):
mouth_x+=55
label3=myfont.render(str(mylives), 1, (20, 255, 0))
label2=myfont.render(str(myscore), 1, (20, 255, 0))
window.blit(backGr,(0,0))
window.blit(mouth, (mouth_x,440))
window.blit(fruit,(fruit_x, fruit_y))
window.blit(label1, (174, 537))
window.blit(label2, (700, 157))
window.blit(label3, (700, 400))
pygame.display.update()
这基本上是一个简单的水果捕捉游戏 我怎么能这样做,如果碗和水果之间没有任何接触,我的生命会下降一个? 我设法得到+1分,但没有-1分。 有什么想法吗? 我是python和pygame的新手,所以它可能非常简单,我没有想过。
答案 0 :(得分:1)
如果你希望它在你错过的时候失去生命,或者如果你击中了你的分数,那么就使用别的。如果你击中,+1得分,否则,-1生命。这是一个例子:
if fruit_x>=mouth_x and fruit_x<=mouth_x+300 :
myscore+=1
fruit_y=600#move it off screen
pygame.mixer.music.load('data/eating.wav')
else:
mylives-=1