我需要在表单中使用select2对象。这是我的表单 http://i.stack.imgur.com/jVILq.jpg
有许多选择的html对象。
例如,如果我想将Customers选择框更改为Select2对象,我已经在jsfiddle.net上发布了这一小段代码,但我无法为每个选择创建此函数的副本,因为它太难维护
我如何抽象它?
我在此处发布了一个示例:http://jsfiddle.net/GcJgU/7/
我已经从用户Flip找到了一个潜在的解决方案,但它还没有完成,因为我需要将这个JQuery对象应用于页面中所有输入隐藏的html对象。
这是一个例子:
$(".select2").select2({
ajax: {
url: $(this).attr("url-search") + "/term/",
dataType: 'json',
cache: true,
data: function (term, page) {
return {
term: term
};
},
results: function (data) {
var results = [];
$.each(data, function (index, item) {
var id = $(this).attr("field-id");
var fieldname = $(this).attr("fields-data");
results.push({
id: item[id],
text: item[fieldname]
});
});
return {
results: results
};
},
},
formatResult: function (object, container, query) {
console.log(object);
},
initSelection: function (element, callback) {
var id = $(element).val();
var fieldid = $(element).attr("field-id");
var fieldname = $(element).attr("fields-data");
$.ajax($(element).attr("url-searchid") + "/term/" + id, {
dataType: "json"
}).done(function (items) {
var data = {
id: items[0][fieldid],
text: items[0][fieldname]
};
callback(data);
});
}
});
似乎没有读取$(this).attr(“url-search”)并且搜索过程没有启动。我不明白为什么。
谢谢你们
答案 0 :(得分:0)
function select2Factory(select2) {
return {
minimumInputLength: 3,
ajax: {
url: select2.attr("callback-url"),
dataType: 'json',
cache: true,
data: function (term, page) {
return {
term: term
};
},
results: function (data) {
var results = [];
$.each(data, function (index, item) {
var $this = $(this);
var id = select2.attr("field-id");
var fieldname = select2.attr("field-data");
results.push({
id: item[id],
text: item[fieldname]
});
});
return {
results: results
};
},
},
initSelection: function (element, callback) {
var id = $(element).val();
var fieldid = select2.attr("field-id");
var fieldname = select2.attr("field-data");
$.ajax("/admin/customers/searchbyid/term/" + id, {
dataType: "json"}).done(function(items) {
var data = {id: items[0][fieldid], text: items[0][fieldname] };
callback(data);
});
}
}
}
$el = $("#customer_id");
$el.select2(select2Factory($el));
答案 1 :(得分:0)
由于Flip,我已经解决了这个问题:
<强> HTML:强>
<input type="hidden" id="customer_id" title="" required="1" class="form-control select2 select2-offscreen" url-searchid="/admin/customers/searchbyid" url-search="/admin/customers/search" fields-data="lastname firstname ( company )" field-id="customer_id" value="12" name="customer_id" tabindex="-1">
<强> JQUERY:强>
function select2Factory(select2) {
return {
ajax: {
url: select2.attr("url-search") + "/term/",
dataType: 'json',
cache: true,
data: function (term, page) {
return {
term: term
};
},
results: function (data) {
var results = [];
$.each(data, function (index, item) {
var id = select2.attr("field-id");
var field_data = select2.attr("fields-data");
var i;
mask = field_data.split(' ');
mask_length = mask.length;
output = '';
for (i = 0; i < mask_length; i++) {
if (i > 0) output += ' ';
field = item[mask[i]];
if (typeof field === 'undefined') {
output += mask[i];
} else {
output += field;
}
}
results.push({
id: item[id],
text: output
});
});
return {
results: results
};
},
},
initSelection: function (element, callback) {
var id = $(element).val();
var fieldid = select2.attr("field-id");
var field_data = select2.attr("fields-data");
var i;
mask = field_data.split(' ');
mask_length = mask.length;
$.ajax(select2.attr("url-searchid") + "/term/" + id, {
dataType: "json"}).done(function(items) {
output = '';
for (i = 0; i < mask_length; i++) {
if (i > 0) output += ' ';
field = items[0][mask[i]];
if (typeof field === 'undefined') {
output += mask[i];
} else {
output += field;
}
}
var data = {id: items[0][fieldid], text: output };
callback(data);
});
}
};