Question

现在被困在这几天，我出去了。基本上我已经将2D数组值（一个图像，我知道有更简单的方法来实现这个，但我有明确的要求）转换为一维数组。我可以轻松旋转2D阵列。我在旋转阵列的1D版本时遇到了麻烦，我认为这是由于单行算法不正确。我用来旋转数组的代码是：

cout << "\nTransfer from 2D to dynamic 1D array and print details\n\n";
myImage * p_myImage = new myImage[total];

    for (int y = 0; y < height; y++)
{
    for (int x = 0; x < width; x++)
    {
        int offset = width * y + x;
        p_myImage[offset].pixel = array2D[y][x];
        cout << p_myImage[offset].pixel << " ";
    }
  cout << "\n";
}

//new pointer to copy to
myImage * p_myImage2 = new myImage[total];
cout << "\nRotate Matrix through 1D array\n\n";

for (int x = 0; x < width; x++)
{
    for (int y = 0; y < height; y++)
    {
        int offset = height * x + y;
        //int offset = width * y + x ;
        p_myImage2[offset].pixel = p_myImage[height-1+x].pixel;
        cout << p_myImage2[offset].pixel << " ";
    }
  cout << "\n";
}

Answer 1

这应该顺时针旋转：

p_myImage2[offset].pixel = p_myImage[width * (height - 1 - y) + x].pixel;

顺时针旋转2D转换的1D阵列90度

1 个答案: