Question

我需要从两个表中获取所有列（包括重复列）。我获取了所有数据，但重复列没有对别名的任何引用。我觉得数据应该像这样回来（但事实并非如此。）：

[0] => Array
        (
            [0] => 1
            [Alias1.id] => 1
            [1] => bay area
            [Alias1.city] => bay area
            [2] => CA
            [Alias1.state] => CA
            [3] => 1
            [Alias2.id] => 1
            [4] => san francisco
            [Alias2.city] => san francisco
            [5] => giants
            [Alias2.baseball_team] => giants
        )

但相反，数据会像这样回来：

[0] => Array
        (
            [0] => 1
            [id] => 1
            [1] => bay area
            [city] => bay area
            [2] => CA
            [state] => CA
            [3] => 1
            [4] => san francisco
            [5] => giants
            [baseball_team] => giants
        )

以下是查询：

$result = mysqli_query($sql, SELECT  Alias1.id, Alias1.city, Alias1.state, Alias2.id, Alias2.city, Alias2.baseball_team 
          FROM database.table1 AS Alias1 
          LEFT JOIN database.table2 AS Alias2 
          ON Alias1.id = Alias2.id
)

以下是我获取数据的方式：

while($row = mysqli_fetch_array($result))
{
     $data[] = $row;
}
print_r($data);die();

此问题是 How to return mysql data using table aliases with left join and duplicate columns

的精确问题

Answer 1

以这种方式试试

SELECT Alias1.id `Alias1.id`, 
       Alias1.city `Alias1.city`, 
       Alias1.state `Alias1.state`, 
       Alias2.id `Alias2.id`,
       Alias2.city `Alias2.city`, 
       Alias2.baseball_team `Alias2.baseball_team`
  FROM table1 AS Alias1  LEFT JOIN table2 AS Alias2 
    ON Alias1.id = Alias2.id

示例输出：

| ALIAS1.ID | ALIAS1.CITY | ALIAS1.STATE | ALIAS2.ID |   ALIAS2.CITY | ALIAS2.BASEBALL_TEAM |
|-----------|-------------|--------------|-----------|---------------|----------------------|
|         1 |    bay area |           CA |         1 | san francisco |               giants |

这是 SQLFiddle 演示

Answer 2

它正在做的是正确的，如果您希望将表名作为column_name的一部分，则必须将select语句更改为以下内容：
选择Alias1.id为`Alias1.id`，
        Alias1.city为“Alias1.city”，
        Alias1.state为“Alias1.state”，
        Alias2.id为“Alias2.id”，
        Alias2.city为“Alias2.city”，
        Alias2.baseball_team为“Alias2.baseball_team”

如何使用表别名返回包含重复列的所有数据

2 个答案: