如何将布尔值转换为消息?

时间:2013-11-18 06:30:47

标签: java

我所做的程序基本上是用于将密码限制为6-10个字符并且至少需要1个字符和1个密码的密码。如何获取布尔值并将其转换为消息。我正在为Japplet UI使用另一个类,这就是我想要传递它的原因。

编辑:当我的其他课程获得用户输入时,我不明白该怎么做。

import java.awt.Container;
import java.awt.FlowLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

import javax.swing.JApplet;
import javax.swing.JButton;
import javax.swing.JLabel;
import javax.swing.JTextField;



    public class PasswordUI extends JApplet implements ActionListener {

        JLabel passwordLabel = new JLabel("");
        JTextField inputBox = new JTextField(40);
        JButton goButton = new JButton("Go");
        Container con = getContentPane();

        public void init()
        {
            con.setLayout(new FlowLayout());
            con.add(new JLabel("Enter a password between 6-10 characters. Must contain atleast 1 number and 1 letter"));
            con.add(inputBox);
            con.add(goButton);
            con.add(passwordLabel);

            goButton.addActionListener(this);
            inputBox.addActionListener(this);
        }
        public void actionPerformed(ActionEvent e)
        {
            String userInput = inputBox.getText();

            boolean pass= Password.check(userInput);
            //String message = Password.display(null);
            Password mess= new Password();

            passwordLabel.setText( mess.getDisplay());



        }
        }

    public class Password {

        public static boolean check(String str)
        {

        boolean result = false;
        char ch;
        int letterCount = 0,
                digitCount= 0 ;
        int length = str.length();

        if(str.length()>= 6)

        {
            if(str.length()<= 10)
            {
                for (int i=0; i<length; i++ ) //i<end 
                {
                    ch = str.charAt(i);
                    if (Character.isDigit(ch))
                        digitCount++;
                    else if (Character.isLetter(ch))
                        letterCount++;
                }

                if (letterCount >= 1 && digitCount >= 1)
                    result = true;
                }
            }
        return result;
        }


        public String getDisplay()

        {


        String message = "";

        if( Password.check(null) == true)          This is what I'm having trouble whit
        {
            message = "The Password meets the requirements";
        }
        else
        {
        message =   "Your password does not match the requirements";
        }


            return message;
        }
    }

2 个答案:

答案 0 :(得分:2)

写点像

String myMessage = result ? "Your password is valid" : "You failed";

问号意味着 - 查看左侧的布尔表达式。如果这是真的,那就回报下一个;如果它是假的,返回结肠后的内容。

答案 1 :(得分:2)

您需要检查密码并相应地分配您的信息。

if( Password.check(null) == true) // This just passes null instead of the password string to the check method.

您需要将实际密码字符串发送到check方法,而不是null。

if( Password.check(yourPasswordString) == true) // Send your password value got from the user

为了进一步简化,您可以删除==支票。

if( Password.check(yourPasswordString))

为了进一步简化,您可以使用三元运算符David提及此类

String myMessage = Password.check(yourPasswordString) ? "Your password is valid" : "You failed";

修改

看到你的编辑后,这就是你需要做的。

将布尔结果传递给getDisplay()方法。

// inside init() method
boolean pass= Password.check(userInput);
Password mess= new Password();
passwordLabel.setText(mess.getDisplay(pass)); // passing the boolean to the getDisplay method
...
// getDisplay method.
public String getDisplay(boolean result) {
    return result ? "The Password meets the requirements" : "Your password does not match the requirements";
}

您甚至可以将getDisplay()作为static方法,并将其称为此类。

// inside init() method
boolean pass= Password.check(userInput);
// static method, hence mess object is not required.
passwordLabel.setText(Password.getDisplay(pass)); // passing the boolean to the getDisplay method
...
// getDisplay method.
public static String getDisplay(boolean result) { // static method
    return result ? "The Password meets the requirements" : "Your password does not match the requirements";
}