我想以一些聪明的方式使用渐变生成画布图像。我希望图像看起来像这样:
我无法理解它。我需要在窗体和圆弧中生成线条 - 或者以一些聪明的方式使用带有颜色停止的渐变。如果我转换为HSL并且只是通过HUE值会更容易吗?
例如,我可以用矩形格式
for (var i = 0; i < h; ++i) {
var ratio = i/h;
var hue = Math.floor(360*ratio);
var sat = 100;
var lum = 50;
line(dc, hslColor(hue,sat,lum), left_margin, top_margin+i, left_margin+w, top_margin+i);
}
有没有人有关于如何使用画布生成此图像的任何聪明提示?
答案 0 :(得分:12)
这不完美(由于绘图步骤...),但它可以帮助你:
HTML:
<canvas id="colors" width="200" height="200"></canvas>
使用Javascript:
var canvas = document.getElementById("colors");
var graphics = canvas.getContext("2d");
var CX = canvas.width / 2,
CY = canvas.height/ 2,
sx = CX,
sy = CY;
for(var i = 0; i < 360; i+=0.1){
var rad = i * (2*Math.PI) / 360;
graphics.strokeStyle = "hsla("+i+", 100%, 50%, 1.0)";
graphics.beginPath();
graphics.moveTo(CX, CY);
graphics.lineTo(CX + sx * Math.cos(rad), CY + sy * Math.sin(rad));
graphics.stroke();
}
这个想法是逐行绘制光盘,其色调值对应于行方向。
您可以通过向 rad 变量添加半径角来更改颜色基础旋转(将-pi / 2添加到 rad 会使渐变看起来像您的图形)。
答案 1 :(得分:0)
这是一种采用稍微更具功能性的方法的替代方法:
var canvas = document.getElementById("radial"),
ctx = canvas.getContext("2d"),
width = canvas.width,
height = canvas.height,
center = { x: width/2, y: height/2 },
diameter = Math.min(width, height);
var distanceBetween = function(x1,y1,x2,y2) {
// Get deltas
var deltaX = x2 - x1,
deltaY = y2 - y1;
// Calculate distance from center
return Math.sqrt(deltaX*deltaX+deltaY*deltaY);
}
var angleBetween = function(x1,y1,x2,y2) {
// Get deltas
var deltaX = x2 - x1,
deltaY = y2 - y1;
// Calculate angle
return Math.atan2(deltaY, deltaX);
}
var radiansToDegrees = _.memoize(function(radians) {
// Put in range of [0,2PI)
if (radians < 0) radians += Math.PI * 2;
// convert to degrees
return radians * 180 / Math.PI;
})
// Partial application of center (x,y)
var distanceFromCenter = _.bind(distanceBetween, undefined, center.x, center.y)
var angleFromCenter = _.bind(angleBetween, undefined, center.x, center.y)
// Color formatters
var hslFormatter = function(h,s,l) { return "hsl("+h+","+s+"%,"+l+"%)"; },
fromHue = function(h) { return hslFormatter(h,100,50); };
// (x,y) => color
var getColor = function(x,y) {
// If distance is greater than radius, return black
return (distanceFromCenter(x,y) > diameter/2)
// Return black
? "#000"
// Determine color
: fromHue(radiansToDegrees(angleFromCenter(x,y)));
};
for(var y=0;y<height;y++) {
for(var x=0;x<width;x++) {
ctx.fillStyle = getColor(x,y);
ctx.fillRect( x, y, 1, 1 );
}
}
它使用一个函数来计算每个像素的颜色 - 这不是最有效的实现,但也许你会收集一些有用的东西。
请注意,bind()
用于某些辅助函数,例如memoize
- 部分应用程序 - 以及{{1}}。
underscore用于实验。
答案 2 :(得分:0)
小调整使其具有白色中心
var canvas = document.getElementById(&#39; colorPicker&#39;); var graphics = canvas.getContext(&#34; 2d&#34;);
var CX = canvas.width / 2,
CY = canvas.height / 2,
sx = CX,
sy = CY;
for (var i = 0; i < 360; i += 0.1) {
var rad = i * (2 * Math.PI) / 360;
var grad = graphics.createLinearGradient(CX, CY, CX + sx * Math.cos(rad), CY + sy * Math.sin(rad));
grad.addColorStop(0, "white");
grad.addColorStop(0.01, "white");
grad.addColorStop(0.99, "hsla(" + i + ", 100%, 50%, 1.0)");
grad.addColorStop(1, "hsla(" + i + ", 100%, 50%, 1.0)");
graphics.strokeStyle = grad;
graphics.beginPath();
graphics.moveTo(CX, CY);
graphics.lineTo(CX + sx * Math.cos(rad), CY + sy * Math.sin(rad));
graphics.stroke();
}