Question

我正在尝试编译一个c3程序，但我继续收到以下错误。

错误CS1502：string.Join(string, string[])的最佳重载方法匹配包含一些无效参数。

错误CS1503：参数#2无法将char[]表达式转换为string[]类型

for (int row = 0; row < 3; row++)
{
    char[] arr = new char[3];
    for (int col = 0; col < 3; col++)
    {
        if (board[row, col] == Player.None)
        {
            arr[col] = ' ';
        }
        else
        {
            arr[col] = board[row, col] == Player.P1 ? 'X' : 'O';
        }
    }

    Console.WriteLine("| {0} |", string.Join(" | ", arr));

Answer 1

答案很简单，arr是char[]而不是string[]。

试试这个

Console.WriteLine("| {0} |", string.Join(" | ", arr.Select(a => a.ToString())));

Answer 2

您可以迭代数组的char s（as suggested by others），也可以更改数组的类型

for (int row = 0; row < 3; row++)
{
    var arr = new string[3];
    for (int col = 0; col < 3; col++)
    {
        if (board[row, col] == Player.None)
        {
            arr[col] = " ";
        }
        else
        {
            arr[col] = board[row, col] == Player.P1 ? "X" : "O";
        }
    }

    Console.WriteLine("| {0} |", string.Join(" | ", arr));
}

Answer 3

由于您的arr类型为char[]，您可以使用String(char[])构造函数创建string对象实例

var strData= new string[]{new string(arr)};
Console.WriteLine("| {0} |", (string.Join(" | ", strData));

将char []转换为string []的C＃编译错误

3 个答案: