如何请求在ios中有空格和点的网址？

Question

我正在尝试请求以下网址，并且收到错误消息“数据参数为零”。我发现'seller_name'有空格，'amount'有点（。）。我认为这是由URL引起的问题。那么有没有办法发送有空格和点的URL而不丢失信息？

NSURL *url1 = [[NSURL alloc]initWithString:[NSString stringWithFormat:@"192.168.1.85/localex_postsale.html?contactid=%@&exchangeid=%@&token=%@&buyerid=%@&seller_name=%@&desc=%@&amount=%@&sellerid=%@",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]];
NSError *errors1;
NSData *data1 = [NSData dataWithContentsOfURL:url1];
NSDictionary *json1 = (NSDictionary *)[NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:&errors1];

Answer 1

查看-stringByAddingPercentEscapesUsingEncoding:中的NSString方法，例如：

NSString *myUnencodedString = [NSString stringWithFormat:@"192.168.1.85/localex_postsale.html?contactid=%@&exchangeid=%@&token=%@&buyerid=%@&seller_name=%@&desc=%@&amount=%@&sellerid=%@",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]
NSString *encodedString = [myUnencodedString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *myURL = [[NSURL alloc] initWithString:encodedString]
...

Cf。：Apple documentation。

Answer 2

这是因为网址不应包含空格。如果有空格，它应该编码为%20。我们可以使用NSString对NSUTF8StringEncoding中的空格和特殊字符进行编码，如下所示

NSString *string = [[NSString stringWithFormat:@"192.168.1.85/localex_postsale.html?contactid=%@&exchangeid=%@&token=%@&buyerid=%@&seller_name=%@&desc=%@&amount=%@&sellerid=%@",contactid,exchangeid,token,buyervalue,sellers,_Description,_Amount,contactid]stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url1 = [[NSURL alloc]initWithString:string];
NSError *errors1;
NSData *data1 = [NSData dataWithContentsOfURL:url1];
NSDictionary *json1 = (NSDictionary *)[NSJSONSerialization JSONObjectWithData:data1 options:kNilOptions error:&errors1];