Question

我在iphone地址簿中有一个手机号码，如0413 588 266

ABMutableMultiValueRef phoneno  = ABRecordCopyValue(person, kABPersonPhoneProperty);

    NSString *phone;
    if(ABMultiValueGetCount(phoneno) > 0) 
    {
        phone =  (__bridge NSString *)ABMultiValueCopyValueAtIndex(phoneno, 0);

    }
    NSLog(@"phone%@",phone);

当我导入该号码时，它在IOs7中给出phone（null）值我对Ios6没有任何问题。任何帮助都会受到赞赏。谢谢你。

Answer 1

Try this way...

<强> ViewController.h

#import <UIKit/UIKit.h>
#import <AddressBook/AddressBook.h>
#import <AddressBookUI/AddressBookUI.h>
@interface ViewController : UIViewController
<ABPeoplePickerNavigationControllerDelegate>

@property (nonatomic, retain) ABPeoplePickerNavigationController *contacts;
-(IBAction)btn_press:(id)sender;
@end

<强> ViewController.m

-(IBAction)btn_press:(id)sender
{
    contacts = [[ABPeoplePickerNavigationController alloc] init];

    // Set the delegate.
    [contacts setPeoplePickerDelegate:self];
    [contacts setDisplayedProperties:[NSArray arrayWithObject:[NSNumber numberWithInt:kABPersonPhoneProperty]]];
    [self presentViewController:contacts animated:YES completion:nil];

}

    #pragma mark - AddressBook Delegate Methods

    -(BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person{
        return YES;
    }


    -(BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier{



NSString *firstName = (__bridge NSString *)ABRecordCopyValue(person, kABPersonFirstNameProperty);

    ABMutableMultiValueRef phoneno  = ABRecordCopyValue(person, kABPersonPhoneProperty);

    NSString *phone;
      phone =  (__bridge NSString *)ABMultiValueCopyValueAtIndex(phoneno, 0);
    NSLog(@"%@",phone); // Prints 0413588266



  **** NEW Update for Dismiss the Picker*******
 [contacts dismissViewControllerAnimated:NO completion:nil];
   return NO:
}

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