好的,我已经看到了很多关于提交表单而没有刷新的事情,我觉得有几种方法可以通过提交或只使用按钮(差异/最好?)来做到这一点而且我仍然遇到pproblems尽管搜索通过无数的帖子。所以:
$(function() {
$('form').on('submit', function(e) {
e.preventDefault();
var privacy = $('input:radio[name=privacy]:checked').val();
var invites = $('input:radio[name=invites]:checked').val();
var posts = $('input:radio[name=posts]:checked').val();
var dataString = 'privacy=' + privacy + '&invites=' + invites + '&posts=' + posts;
alert(dataString);
$.ajax({
type: "POST",
url: "editOptions.php",
data: dataString,
success: function() {
$('#admin').append("<div id='message'</div>");
$('#message').html("Changes Saved");
}
});
return false;
});
});
和
<form action="" method="post" name="editOptions">
Privacy
<input type="radio" name="privacy" id="privacy" value="public"
<?php if($privacy == "public") { ?>checked="checked"<?php } ?>>
Public
<input type="radio" name="privacy" id="privacy" value="private"
<?php if($privacy == "private") { ?>checked="checked"<?php } ?>>
Private
Invites
<input type="radio" name="invites" id="invites" value="adminonly"
<?php if($invite == "adminonly") { ?>checked="checked"<?php } ?>>
Admin Only
<input type="radio" name="invites" id="invites" value="everyone"
<?php if($invite == "everyone") { ?>checked="checked"<?php } ?>>
Everyone
Posts
<input type="radio" name="posts" id="posts" value="adminonly"
<?php if($post == "adminonly") { ?>checked="checked"<?php } ?>>
Admin Only
<input type="radio" name="posts" id="posts" value="everyone"
<?php if($post == "everyone") { ?>checked="checked"<?php } ?>>
Everyone
<button>Save Changes</button>
</form>
所以只是一个包含3组2个单选按钮的表单。所以我认为问题是通过许多教程和帖子我有一个组合,当你“提交”或点击“按钮”时该做什么,但也许其他人可以看到我错过的一些容易。
TY
编辑editOptions以防万一
<?php
include 'config.php';
$privacyX = $_POST['privacy'];
$invitesX = $_POST['invites'];
$postsX = $_POST['posts'];
$groupAd = $_POST['groupName'];
$sql = "UPDATE `options` SET privacy='$privacyX', invite='$invitesX', post='$postsX' WHERE adminGroup = '$groupAd'";
if(!mysql_query($sql, $link))
{
die('Error: ' . mysql_error());
}
mysql_close($link);
?>
答案 0 :(得分:1)
完整的工作示例:
<script type="text/javascript">
$(function() {
$('.button1').click(function(e) {
e.preventDefault();
var privacy = $('input:radio[name=privacy]:checked').val();
var invites = $('input:radio[name=invites]:checked').val();
var posts = $('input:radio[name=posts]:checked').val();
console.log(privacy, invites, posts);
//return;
//alert(dataString);
$.ajax({
type: "POST",
url: "editOptions.php",
data: {privacy: privacy, invites: invites, posts: posts},
success: function(result) {
$('#admin').append("<div id='message'>Changes Saved</div>");
console.log(result);
console.log("success");
}
});
});
});
</script>
</head>
<body>
<div id="admin">
</div>
<form action="" method="post" name="editOptions">
Privacy
<input type="radio" name="privacy" id="privacy" value="public" >
Public
<input type="radio" name="privacy" id="privacy" value="private" >
Private
Invites
<input type="radio" name="invites" id="invites" value="adminonly" >
Admin Only
<input type="radio" name="invites" id="invites" value="everyone" >
Everyone
Posts
<input type="radio" name="posts" id="posts" value="adminonly" >
Admin Only
<input type="radio" name="posts" id="posts" value="everyone" >
Everyone
<button class="button1">Save Changes</button>
</form>
</body>
答案 1 :(得分:0)
全部排序。这是editOptions的问题,而不是传递正确的变量名称。 :P TY