我唯一的问题是页面无法加载自动刷新,因此当我刷新页面时它正在加载。
这是我的html和ajax代码及其数据库。
我的触发按钮
<?php
$data = mysqli_query($con,"SELECT * FROM announcement");
$count = mysqli_num_rows($data);
if ($count != 0) {
while($row = mysqli_fetch_array($data)) {
echo '
<button class="btn btn-danger nav-link delannouncement" id="delannouncement">Resume System</button>';
$dataid = $row['id'];
}
}else{
echo '<button class="btn btn-primary nav-link announcement" id="announcement">Passenger Announcement</button>';
}
?>
在数据库
中获取数据
这是我在mysql中将数据从ajax调用到这里的地方。
$data = mysqli_query($con,"SELECT * FROM announcement");
$count = mysqli_num_rows($data);
if ($count != 0) {
while($row = mysqli_fetch_array($data)) {
echo '<div id="myModal" class="modal" style="position:fixed; display: none; padding-top: 100px;
left: 0; top: 0; width: 100%; height: 100%; overflow: auto; background-color: rgb(0,0,0); background-color: rgba(0,0,0,0.9); ">
<div class="container" style="width: 100%">
<div class="card col-12" style="background-color: red; color: white;">
<div class="card-header">
<p><h3 class="text-center">Announcement</h3></p>
</div>
<div class="card-body text-center">
<h5>'.$row['additional_info'].'</h5>
<p>Please click refresh button to resume after the announcement</p>
</div>
</div>
</div>
<img class="modal-content" id="img01">
</div>';
$dataid = $row['id'];
}
}
?>
</div>
<script>
document.getElementById('myModal').style.display='block';
我的 AJAX代码 这是我的AJAX代码,这是我单击按钮后模态无法立即加载的问题,在它起作用之前,我需要刷新页面以解决此问题 >
$('.announcement').on("click", function () {
$.confirm({
title: 'Announcement',
content: '' +
'<form action="" class="formName">' +
'<div class="form-group">' +
'<label>Announcement Info</label>' +
'<input type="text" placeholder="Enter announcement here" class="add-info form-control" required />' +
'</div>' +
'</form>',
buttons: {
formSubmit: {
text: 'Submit',
btnClass: 'btn-blue',
action: function () {
var addInfo = this.$content.find('.add-info').val();
$.confirm({
type: 'red',
theme: 'material',
title: 'Are you sure you want to make an announcement?',
content:'<strong>Announcement Info:</strong> ' + addInfo,
buttons: {
Yes: {
btnClass: 'btn-green',
action: function () {
$.ajax({
type: "POST",
url: "announcement.php",
data: {
addInfo: addInfo
},
dataType: "text",
success: function (data) {
window.location.replace("change-password.php");
},
error: function (err) {
console.log(err);
}
});
}
},
No: {
text: 'No', // With spaces and symbols
action: function () {
$.alert('Announcement Cancelled');
}
}
}
});
}
},
cancel: function () {
//close
},
},
onContentReady: function () {
// bind to events
var jc = this;
this.$content.find('form').on('submit', function (e) {
// if the user submits the form by pressing enter in the field.
e.preventDefault();
jc.$$formSubmit.trigger('click'); // reference the button and click it
});
}
});
});
我是ajax编码的新手,语法可以帮助我完成这个项目。
答案 0 :(得分:0)
$('.announcement').on("click", function () {
$.confirm({
///YOUR LONG CODE
});
//ALL YOU NEED
return false;
});
在表单内提交按钮时,触发事件时返回false即可。:)