Question

我的查询如下：

AS
BEGIN
SET NOCOUNT ON;
BEGIN
           SELECT *
    FROM   (SELECT [id],
                   [account],
                   [tag],
                   [location],
                   [whoAdded],
                   ROW_NUMBER() OVER (PARTITION BY whoAdded ORDER BY id DESC) AS rn
            FROM   accountLogAccounts) AS a
    WHERE  rn = 1
    FOR    XML PATH ('users'), TYPE, ELEMENTS, ROOT ('root');
END
END

我正在尝试在此处包含用户帐户总数以及所有代码的计数。

表格如下：

id, account, tag, whoAdded
1, 123, dog, bob
2, 123, cat, jon
3, 125, pig, bob

预期结果：

用户Bob拥有2个不同的帐户和2个标签

用户jon有1个不同的帐户和1个标签

Answer 1

Select count(distinct whoAdded), count(distinct tag), whoadded
FROM accountLogAccounts
group by whoadded

应该返回

2, 2, bob
1, 1, jon

如果您需要实际文本，请相应地应用字符串连接。

计算SQL中的问题

1 个答案: