我已经解析了xml文档,并使用for循环来循环获取字符串中的不同值,但是当我尝试返回值时,我只得到最后获得的值,我想返回所有单个值,以便我可以以任何文件格式存储该值, 以下是我的代码,
XmlDocument xmlDOC = new XmlDocument();
xmlDOC.LoadXml(periodID_Value_Before_OffSet); // string storing my XML
var value = xmlDOC.GetElementsByTagName("value");
var xmlActions = new string[value.Count];
string values = "";
string Period1 = "";
string periodlevel_period1 = "";
var listOfStrings = new List<string>();
string modified_listofstrings = listOfStrings.ToString();
string arrayOfStrings = "";
for (int i = 0; i < value.Count; i++)
{
var xmlAttributeCollection = value[i].Attributes;
if (xmlAttributeCollection != null)
{
var action = xmlAttributeCollection["periodid"];
xmlActions[i] = action.Value;
values += action.Value + ",";
string vals = values.Split(',')[1];
string counts = values;
string[] periods = counts.Split(',');
Period1 = periods[i];
// periodlevel_period1 = Client.GetAttributeAsString(sessionId, Period1, "name", "");
modified_listofstrings = Client.GetAttributeAsString(sessionId, Period1, "name", "");
modified_listofstrings.ToArray().ToString();
//listOfStrings = periodlevel_period1;
}
}
return modified_listofstrings;
这个modified_listofstrings字符串只返回最后一个值,我想返回循环时获得的所有值的数组。
----------更新的问题---------- 下面是我的Sample XMl
<string xmlns="http://tempuri.org/">
<ResultSetHierarchy totalResultsReturned="1" totalResults="1" firstIndex="0" maxCount="-1">
<object id="SC.1938773693.238">
<measure.values>
<series id="SC.1938773693.108280985">
<value periodid="SC.1938773693.394400760" value="17" />
<value periodid="SC.1938773693.1282504058" value="15" />
<value periodid="SC.1938773693.1631528570" value="13" />
</series>
</object>
</ResultSetHierarchy>
</string>
我希望输出为“SC.1938773693.394400760”:“17”等等所有句号
答案 0 :(得分:2)
根据提供的信息,我更新了答案。
List<string> items = new List<string>();
XmlDocument xmlDOC = new XmlDocument();
xmlDOC.Load(@"E:\Delete Me\ConsoleApplication1\ConsoleApplication1\bin\Debug\List.xml");
var elements = xmlDOC.GetElementsByTagName("value");
foreach (var item in elements)
{
XmlElement value = (XmlElement)item;
items.Add(string.Format("{0}:{1}", value.GetAttribute("periodid"), value.GetAttribute("value")));
}
答案 1 :(得分:0)
看起来你正试图:
如果这是正确的,以下方法应该做你需要的:
public List<string> GetListOfData()
{
XmlDocument xmlDOC = new XmlDocument();
xmlDOC.LoadXml("<Html><value periodid='Yabba'>YabbaValue</value><value periodid='Dabba'>DabbaValue</value><value periodid='Doo'>DooValue</value></Html>"); // string storing my XML
var value = xmlDOC.GetElementsByTagName("value");
var listOfStrings = new List<string>();
for (int i = 0; i < value.Count; i++)
{
var xmlAttributeCollection = value[i].Attributes;
if (xmlAttributeCollection != null)
{
var action = xmlAttributeCollection["periodid"];
string Period1 = action.Value;
listOfStrings.Add(QPR_webService_Client.GetAttributeAsString(sessionId, Period1, "name", "") + ":" + value[i].InnerText);
}
}
return listOfStrings;
}