我正在尝试获取数据库中的所有记录,并在表中逐行显示它们。它只是一次又一次地显示相同的行。如何让表格的每一行显示数据库中的下一个结果?
<?php
// Formulate query
$logo = "SELECT logo from stores";
$cat = "SELECT cat from stores";
$commission = "SELECT commission from stores";
$link = "SELECT link from stores";
$name = "SELECT name from stores";
// Perform query
$result1 = mysql_query($logo) or die;
$result2 = mysql_query($cat) or die;
$result3 = mysql_query($commission) or die;
$result4 = mysql_query($link) or die;
$result5 = mysql_query($name) or die('Something went wrong');
//////////////////////////////////////
//////////////////////////////////////
do {
//////////////////////////////////////
$rlogo = mysql_fetch_assoc($result1);
$a = implode($rlogo);
//////////////////////////////////////
$rcat = mysql_fetch_assoc($result2);
$b = implode($rcat);
//////////////////////////////////////
$rcommission = mysql_fetch_assoc($result3);
$c = implode($rcommission);
//////////////////////////////////////
$rlink = mysql_fetch_assoc($result4);
$d = implode($rlink);
//////////////////////////////////////
$rname = mysql_fetch_assoc($result5);
$e = implode($rname);
//////////////////////////////////////
$x = $x + 1;
} while ($x <= 1);
?>
答案 0 :(得分:1)
如果你增加$ x但是如果循环达到1则循环结束......它会立即结束吗?
$x = $x + 1;
} while ($x <= 1);
通常,人们会这样设置:
$query = "select logo, cat, commission, link, name from stores";
$result = mysql_query($query);
print "<table>";
// table headers
print "<tr><th>logo</th>
<th>cat</th>
<th>comission</th>
<th>link</th>
<th>name</th></tr>";
while($row = mysql_fetch_assoc($result))
{
print "<tr>";
foreach ($row as $column => $value)
{
print "<td>".$value."</td>";
}
// or you can print the table cells like this:
// <td> $row['logo'] </td>
// <td> $row['cat'] </td>
// <td> $row['commission']</td>
// <td> $row['link'] </td>
// <td> $row['name'] </td>
print "</tr>";
}
print "</table>;
此外,mysql_
函数已过时,很快就会从PHP中删除,因此如果您正在学习,则应该学习PDO
或mysqli_
。