用于在同一用户的单行中显示重复日期的SQL查询

Question

请帮我解决SQL查询

＆＃xA;＆＃xA;

这是我的表

＆＃xA;＆＃xA;

  +  - ------ + ---------- +＆＃xA; | UserID | Date |＆＃xA; + -------- + --------- -  +＆＃xA; | Sanjay | 29/06/2017 |＆＃xA; + -------- + ---------- +＆＃xA; | Sanjay | 30/06 / 2017 |＆＃xA; + -------- + ---------- +＆＃xA; | Sanjay | 26/06/2017 |＆＃xA; + ---- ---- + ---------- +＆＃xA; | Vishal | 29/06/2017 |＆＃xA; + -------- + ------- --- +＆＃xA; | Vishal | 30/06/2017 |＆＃xA; + -------- + ---------- +＆＃xA; | Vasanti | 29 / 06/2017 |＆＃XA + -------- + ---------- +＆＃XA;  

＆＃XA;＆＃XA;

需要以下输出

＆＃xA;＆＃xA;

  + -------- + ---------- + ---- -------- + ------------ + ----------- ----------- + + ---- ---- +＆＃xA; | UserID | Count | Date 1 | Date 2 | Date 3 | Date 4 | Date 5 |＆＃xA; + -------- + ------- --- + ------------ + ------------ + ----------- + -------- --- + -------- +＆＃xA; | Sanjay | 3 | 29/06/2017 | 30/06/2017 | 26/06/2017 | | |＆＃XA + -------- + ---------- + ------------ + ----------- -  + ----------- + ----------- + -------- +＆＃xA; | Vishal | 2 | 29/06/2017 | 30/06/2017 | | | |＆＃XA + -------- + ---------- + ------------ + ----------- -  + ----------- + ----------- + -------- +＆＃xA; | Vasanti | 1 | 29/06/2017 | | | | |＆＃XA + -------- + ---------- + ------------ + ----------- -  + ----------- + ----------- + -------- +＆＃XA;  

＆＃XA ;

Answer 1

SQL Server有 PIVOT 运算符，可以执行此类任务

with cte as
(
    select *, count(userid) over (partition by userid) Counts,
              concat('Date ', row_number() over (partition by UserID  order by (SELECT 1))) SQ
    from table
)

select * from 
(
    select * from cte
)a 
PIVOT (
    MAX(Dates) for SQ IN ([Date 1], [Date 2], [Date 3])
)P
order by 2 desc

全动态枢轴方式

declare @cols varchar(200), @query varchar(2000)

SET @cols = STUFF(
                  (select DISTINCT  ','+QUOTENAME(concat('Date ', row_number() over (partition by UserID  order by (SELECT 1))))
                   from table for xml path('')),1,1, '')

set @query  = 'select * from 
               (
                  select *, 
                         count(userid) over (partition by userid) Counts,
                         concat(''Date '', row_number() over (partition by UserID  order by (SELECT 1))) SQ
                  from table
               )a PIVOT (
                    MAX(Dates) for SQ IN ('+@cols+'))P
               order by 2 desc'

exec (@query)

结果：

UserID  Counts  Date 1      Date 2      Date 3
Sanjay  3       29/06/2017  30/06/2017  26/06/2017
Vishal  2       29/06/2017  30/06/2017  NULL
Vasant  1       29/06/2017  NULL        NULL