$num = array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
在数组$ num中有10个数字。我想用PHP列出所有可能的3号组合。 就像:
1, 2, 3
1, 2, 4
1, 2, 5
etc
修改
感谢所有答案,但如果我想创建6个数字组合,则会出现问题。
$num_array2 = array(1, 2, 3, 4, 5, 6, 7, 8, 11, 12, 13, 15, 16, 18, 19, 20);
foreach($num_array2 AS $value1) {
foreach($num_array2 AS $value2) {
if($value2 == $value1) {
continue;
}
foreach($num_array2 AS $value3) {
if($value3 == $value1 || $value3 == $value2) {
continue;
}
foreach($num_array2 AS $value4) {
if($value4 == $value1 || $value4 == $value2 || $value4 == $value3) {
continue;
}
foreach($num_array2 AS $value5) {
if($value5 == $value1 || $value5 == $value2 || $value5 == $value3 || $value5 == $value4) {
continue;
}
foreach($num_array2 AS $value6) {
if($value6 == $value1 || $value6 == $value2 || $value6 == $value3 || $value6 == $value4 || $value6 == $value5) {
continue;
}
echo "$value1, $value2, $value3, $value4, $value5, $value6 \n<br />";
}
}
}
}
}
}
我无法列出
1, 2, 3, 4, 5, 6
1, 2, 3, 4, 5, 7
etc.
我做错了吗?
答案 0 :(得分:1)
试试这个:
foreach($num AS $value1)
{
foreach($num AS $value2)
{
if($value2 == $value1){
continue;
}
foreach($num AS $value3)
{
if($value3 == $value1 || $value3 == $value2){
continue;
}
echo "$value1, $value2, $value3<br/>";
}
}
}
修改强>
实际上,前面的代码列出了所有排列而不是组合。如果您想要所有组合,请尝试以下方法:
for($value1 = 1; $value1 <= 10; $value1++){
for($value2 = $value1 + 1; $value2 <= 10; $value2++){
for($value3 = $value2 + 1; $value3 <= 10; $value3++){
echo "$value1, $value2, $value3<br/>";
}
}
}
答案 1 :(得分:0)
有些事情......
foreach($num AS $value1)
{
foreach($num AS $value2)
{
foreach($num AS $value3)
{
echo $value1 . ',' . $value2 . ',' . $value3 . '<br>';
}
}
}