Question

我的SQL表（TOTAL_PAR_STATUT）包含以下字段：

DISTRIBUTEUR_ID - receptionDate - STATUS_CHAMP_ID - TOTAL_BY_STATUS

执行查询时：

SELECT tps.DISTRIBUTEUR_ID,
   tps.receptionDate,
   tps.STATUS_CHAMP_ID,
   tps.TOTAL_BY_STATUS
FROM TOTAL_PAR_STATUT tps
WHERE tps.receptionDate between '06-10-2013 00:00:00' AND '06-10-2013 23:59:59'
       AND tps.DISTRIBUTEUR_ID = 1 
       AND STATUS_CHAMP_ID IN (1,2,3,9,10,11,7)
GROUP BY tps.DISTRIBUTEUR_ID, tps.receptionDate, tps.TOTAL_BY_STATUS, tps.STATUS_CHAMP_ID;

它给了我以下结果：

 DISTRIBUTEUR_ID --- receptionDate --- STATUS_CHAMP_ID --- TOTAL_BY_STATUS

     1   ---    '2013-10-06 00:00:00' --- 3  ---            1

     1   ---    '2013-10-06 00:00:00' --- 1  ---            13

我想将结果分组到一行中，以便为我提供以下内容：

     DISTRIBUTEUR_ID --- receptionDate --- TOTAL_WHERE_STATUS_3 --- TOTAL_WHERE_STATUS_1

         1  --- '2013-10-06 00:00:00'   ---  1 ---                  13

谢谢。

Answer 1

使用SUM（CASE WHEN ...）

这未经过测试，但应该让您了解如何获得您想要的东西：

SELECT tps.DISTRIBUTEUR_ID,
   tps.receptionDate,
   SUM(CASE WHEN tps.STATUS_CHAMP_ID = 3 THEN 1 ELSE 0 END)[TOTAL_WHERE_STATUS_3],
   SUM(CASE WHEN tps.STATUS_CHAMP_ID = 1 THEN 1 ELSE 0 END)[TOTAL_WHERE_STATUS_1],
FROM TOTAL_PAR_STATUT tps
WHERE tps.receptionDate between '06-10-2013 00:00:00' AND '06-10-2013 23:59:59'
       AND tps.DISTRIBUTEUR_ID = 1 
       AND STATUS_CHAMP_ID IN (1,2,3,9,10,11,7)
GROUP BY tps.DISTRIBUTEUR_ID, tps.receptionDate

单行上SQL表的结果（SQLServer）

1 个答案: