Question

我遇到的几乎所有类似问题都建议使用PIVOT但我无法理解如何在我的情况下使用它。

这是我的查询

SELECT
    SUM(CONVERT(INT,H01))  as H01,
    SUM(CONVERT(INT,H02)) as H02,
    SUM(CONVERT(INT,H03)) as H03,
    SUM(CONVERT(INT,H04)) as H04,
    SUM(CONVERT(INT,H05)) as H05,
    SUM(CONVERT(INT,H06)) as H06,
    SUM(CONVERT(INT,H07)) as H07,
    SUM(CONVERT(INT,H08)) as H08,
    SUM(CONVERT(INT,H09)) as H09,
    SUM(CONVERT(INT,H10)) as H10,
    SUM(CONVERT(INT,H11)) as H11,
    SUM(CONVERT(INT,H12)) as H12,
    SUM(CONVERT(INT,H13)) as H13,
    SUM(CONVERT(INT,H14)) as H14,
    SUM(CONVERT(INT,H15)) as H15
FROM 
    IslemFisi
WHERE
    (H01 = 1) OR (H02 = 1) OR (H03 = 1) OR (H04 = 1) OR
    (H05 = 1) OR (H06 = 1) OR (H07 = 1) OR (H08 = 1) OR
    (H09 = 1) OR (H10 = 1) OR (H11 = 1) OR (H12 = 1) OR
    (H13 = 1) OR (H14 = 1) OR (H15 = 1)

返回此结果集

+-------+------+------+------+-----+------+-----+------+-----+-----+------+-----+-----+------+-------+
|  H01  | H02  | H03  | H04  | H05 | H06  | H07 | H08  | H09 | H10 | H11  | H12 | H13 | H14  |  H15  |
+-------+------+------+------+-----+------+-----+------+-----+-----+------+-----+-----+------+-------+
| 11802 | 2239 | 1575 | 2230 | 833 | 3189 | 152 | 4234 | 617 | 428 | 2211 | 263 | 783 | 3954 | 15922 |
+-------+------+------+------+-----+------+-----+------+-----+-----+------+-----+-----+------+-------+

我希望将它放在一个列中，但不知道该怎么做。使用pivot需要一些聚合函数，但我现在没有任何东西可以聚合。

Answer 1

;WITH cte AS (
--put your query here
)

SELECT H, [VALUES]
FROM (
    SELECT *
    FROM cte) as p
UNPIVOT (
    [VALUES] FOR H IN (H01, H02, H03, H04 ...etc)
) as unpvt

输出：

H   VALUES
H01 11802
H02 2239
....

将单行结果转换为单列结果

1 个答案: