Question

我已成功将城市飞艇推送通知集成到我的Android应用程序中。我在这里遇到了一个问题，就是apID在首次启动时变为null，然后在第二次启动时，apId正确显示。

这就是我抓住apId的方式：

String apid = PushManager.shared().getAPID();

这是我使用的课程：

public class MyApplication extends Application {

    public static SharedPreferences PREFS_TOKEN;
    public static final String PREFERENCE = "UrbanAirship";
    public static String tokenKey;

       @Override
       public void onCreate(){
           AirshipConfigOptions options = AirshipConfigOptions.loadDefaultOptions(this);
           UAirship.takeOff(this, options);
           PushManager.enablePush();
           Logger.logLevel = Log.VERBOSE;

            // use CustomPushNotificationBuilder to specify a custom layout
            CustomPushNotificationBuilder nb = new CustomPushNotificationBuilder();

            nb.statusBarIconDrawableId = R.drawable.paw;// custom status bar icon

            nb.layout = R.layout.notification;
            nb.layoutIconDrawableId = R.drawable.paw;// custom layout icon
            nb.layoutIconId = R.id.icon;
            nb.layoutSubjectId = R.id.subject;
            nb.layoutMessageId = R.id.message;

            // customize the sound played when a push is received
            // nb.soundUri =
            // Uri.parse("android.resource://"+this.getPackageName()+"/"
            // +R.raw.cat);

            String apid = PushManager.shared().getAPID();

            Logger.info("My Application onCreate - App APID: " + apid);

            PREFS_TOKEN = this.getSharedPreferences(PREFERENCE,
                    Context.MODE_PRIVATE);
            Editor edit = PREFS_TOKEN.edit();

            if (apid != null && apid != "") {
                edit.putString(PREFERENCE, apid);
                edit.commit();
            } else {
                edit.putString(PREFERENCE, apid);
                edit.commit();
            }

            tokenKey = PREFS_TOKEN.getString(PREFERENCE, "");
            System.out.println("---------- - App APID: " + tokenKey);

            PushManager.shared().setNotificationBuilder(nb);
            PushManager.shared().setIntentReceiver(IntentReceiver.class);
       }
    }

我还有一个IntentReceiver类。任何帮助表示赞赏。

Answer 1

我发现原因是延迟，要获得apId，需要一些时间，因此，在你的IntentReceiver类中，你必须等待`PushManager.ACTION_REGISTRATION_FINISHED才能触发。从那里，你可以得到apId：

if (action.equals(PushManager.ACTION_REGISTRATION_FINISHED)) {
            Log.i(logTag,"Registration complete. APID:" + intent.getStringExtra(PushManager.EXTRA_APID)+ ". Valid: "+ intent.getBooleanExtra( PushManager.EXTRA_REGISTRATION_VALID, false));
            // Notify any app-specific listeners
            String apid = PushManager.shared().getAPID();


            Intent launch = new Intent(UAirship.getPackageName()+ APID_UPDATED_ACTION_SUFFIX);
            UAirship.shared().getApplicationContext().sendBroadcast(launch);

        }

使用Urban Airship推送通知在首次启动时将apID返回为null

1 个答案: