我已经按照UA教程获得了我的APID,并在我的Android设备上成功收到测试推送消息。
现在我要做的下一件事是使用JAVA定位我的设备并发送推送消息。 从我目前所见,实现这一目标的最佳方法是使用他们的网络API。
但是,当我尝试发送帖子时,我总会收到以下错误:
java.io.IOException:服务器返回HTTP响应代码:401为URL:https://go.urbanairship.com/api/push/ at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(Unknown Source) 在com.Sender.Sender.main(Sender.java:56)
这是我使用的代码:
package com.Sender;
import java.io.BufferedReader;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.net.Authenticator;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;
public class Sender {
/**
* @param args
*/
public static void main(String[] args) {
try {
String responseString = "";
String outputString = "";
String username = "MWMoRVhmRXOG6IrvhMm-BA";
String password = "ebsJS2iXR5aMJcOKe4rCcA";
MyAuthenticator ma= new MyAuthenticator(username, password);
Authenticator.setDefault(ma);
URL url = new URL("https://go.urbanairship.com/api/push/");
URLConnection urlConnection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) urlConnection;
ByteArrayOutputStream bout = new ByteArrayOutputStream();
String APID = "23eef280-19c8-40fc-b798-788f50e255a2";
String postdata = "{\"android\": {\"alert\": \"Hello from JAVA!\"}, \"apids\": [\""+APID+"\"]}";
byte[] buffer = new byte[postdata.length()];
buffer = postdata.getBytes("UTF8");
bout.write(buffer);
byte[] b = bout.toByteArray();
httpConn.setRequestProperty("Content-Length",
String.valueOf(b.length));
httpConn.setRequestProperty("Content-Type", "application/json");
httpConn.setRequestMethod("POST");
httpConn.setDoOutput(true);
httpConn.setDoInput(true);
OutputStream out = httpConn.getOutputStream();
out.write(b);
out.close();
InputStreamReader isr = new InputStreamReader(
httpConn.getInputStream());
BufferedReader in = new BufferedReader(isr);
while ((responseString = in.readLine()) != null) {
outputString = outputString + responseString;
}
System.out.println(outputString);
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e1) {
e1.printStackTrace();
}
}
}
你能帮我吗?
答案 0 :(得分:0)
HTTP 401表示未经授权的访问。在您的代码中,即使您创建了Authenticator,也没有将其作为post请求标头的一部分提供。这是关于如何为URLConnection设置authenticator 的教程。