运营商<< ,>>特定类的重载失败

时间:2013-11-02 21:00:32

标签: c++ class overloading

istream &operator>>(istream &in, iString &a) {
        string name;
        in>>name;
        iString b(name);
        delete a.chars;
        a=b;
        return in;
}
ostream &operator<<(ostream &out, const iString &a) {
        out<<a.chars<<endl;
        return out;
}

这些是我为结构编写的运算符:

struct iString{
  char * chars;
  unsigned int length;
  unsigned int capacity;

  iString();
  iString(const char *);
  iString(const iString&);
  ~iString();

  iString &operator=(const iString&);
  };

// Add other declarations here:
iString operator+(const iString &a, const iString &b);
iString operator*(const iString &a, unsigned int scalar);
iString operator*(unsigned int scalar, const iString &a);
ostream &operator<<(ostream &out, const iString &b);
istream &operator>>(istream &in, iString &b);

我得到的部分错误:

error: no match for ‘operator>>’ in ‘std::cin >> * a[(((int)which) + -0x00000000000000061)]’
/usr/include/c++/4.4/istream:119: note: candidates are: std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(std::basic_istream<_CharT, _Traits>& (*)(std::basic_istream<_CharT, _Traits>&)) [with _CharT = char, _Traits = std::char_traits<char>]
/usr/include/c++/4.4/istream:123: note:                 std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(std::basic_ios<_CharT, _Traits>& (*)(std::basic_ios<_CharT, _Traits>&)) [with _CharT = char, _Traits = std::char_traits<char>]
/usr/include/c++/4.4/istream:130: note:                 std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(std::ios_base& (*)(std::ios_base&)) [with _CharT = char, _Traits = std::char_traits<char>]
/usr/include/c++/4.4/istream:166: note:                 std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(bool&) [with _CharT = char, _Traits = std::char_traits<char>]
/usr/include/c++/4.4/istream:170: note:                 std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(short int&) [with _CharT = char, _Traits = std::char_traits<char>]
/usr/include/c++/4.4/istream:173: note:                 std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(short unsigned int&) [with _CharT = char, _Traits = std::char_traits<char>]
/usr/include/c++/4.4/istream:177: note:                 std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(int&) [with _CharT = char, _Traits = std::char_traits<char>]
/usr/include/c++/4.4/istream:180: note:                 std::basic_istream<_CharT, _Traits>& std::basic_istream<_CharT, _Traits>::operator>>(unsigned int&) [with _CharT = char, _Traits = std::char_traits<char>

我在客户端模块(main)中使用结构的部分方式:

switch(c) {
      case 'r':
        cin >> which;  // Reads a, b, c, or d
        a[which-'a'] = new iString;
        cin >> *(a[which-'a']);
        break;
      case 'w':
        cin >> which;  // Reads a, b, c, or d
        cout << *(a[which-'a']) << endl;
        break;
      case 'n':
        cin >> which >> temp;
        a[which-'a'] = new iString(temp.c_str());
        break;
      case 'i':
        cin >> op1 >> op2;
        a[op1-'a'] =

注意:字段字符是指分配的矢量堆

客户端模块中的变量定义(主要):

int main() {
  bool done = false;
  string temp;
  iString *a[4];
  while(!done) {
    char c;
    char which;
    char op1;
    char op2;
    int int_op;
    cerr << "Command?" << endl;  // Valid commands:  r [a-d] string
                                 //                  wa, wb, wc, wd, q
                                 //                  s[a-d][a-d][a-d]
                                 //                  t [a-d] [a-d] string
                                 //                  m [a-d] int [a-d]
                                 //                  p [a-d] [a-d] int
                                 //                  n [a-d] string
                                 //                  i [a-d] [a-d]
                                 //                  = [a-d] [a-d]
                                 //                  f [a-d] 
                                 //                  e [a-d]
                                 //                  l [a-d]
    cin >> c;  // Reads r, p, m, s, w, n, i, e, f, q
    if (cin.eof()) break;

我将此定义用于赋值运算符:

iString& iString::operator=(const iString &b) {
        chars=new char[strlen(b.chars)+1];
        strcpy(chars, b.chars);
        length=capacity=b.length;
        return *this;
}

更改为删除[] ...;删除数组的正确语法,并在包含类定义的文件中放入“using namespace std”,我得到了新的错误: 在istring.cc:3中包含的文件中:

istring.h:21: error: expected constructor, destructor, or type conversion before ‘&’ token
istring.h:22: error: expected constructor, destructor, or type conversion before ‘&’ token
istring.cc: In function ‘std::istream& operator>>(std::istream&, iString&)’:
istring.cc:59: error: no matching function for call to ‘iString::iString(std::string&)’
istring.cc:19: note: candidates are: iString::iString(const iString&)
istring.cc:11: note:                 iString::iString(const char*)
istring.cc:7: note:                 iString::iString()
istring.h:21: error: expected constructor, destructor, or type conversion before ‘&’ token
istring.h:22: error: expected constructor, destructor, or type conversion before ‘&’ token

2 个答案:

答案 0 :(得分:0)

你应该试试;

cout << a[which-'a'] << endl;
cin >> a[which-'a'];

答案 1 :(得分:0)

这是您的问题:您正在尝试使用name的{​​{1}}参数调用构造函数。您声明了三个构造函数,但没有一个构造函数使用std::string

std::string

如果您尝试以下内容,就像您在代码中的其他地方使用过一样,该怎么办?

    string name;
    in>>name;
    iString b(name);

另外,如果你明确表示你想要一个整数来索引你的指针数组呢?

    iString b(name.c_str());  // use iString(const char *);

它会使您的代码更清晰,并避免在编译器错误中显示偏移量。