Question

我有一张包含游戏列表的表格，它有团队ID和游戏中的分数。

这是表结构。

ID  HOMETEAM    HOMETEAMSCORE   AWAYTEAM    AWAYTEAMSCORE

游戏中每支球队的得分将分别列在各栏中。
当比赛未开始时，两队的得分均为0。
当游戏结束时，任何游戏都不能有0-0的分数。

我需要获得2个特定球队的比赛记录。例如，对于第1队和第2队，我需要输出为1-3，这意味着第1队已经赢得了一次对阵第2队，第2队已经赢得3次对阵第1队。

我正在使用下面的SQL，它在一定程度上起作用。但是对于尚未开始的比赛，我需要输出为0-0（得分为0-0）。

SELECT least(homeTeam, awayTeam) team1,
       greatest(homeTeam, awayTeam) team2,
       sum(case when awayTeam > homeTeam
          then case when homeTeamScore > awayTeamScore then 1 else 0 end else case when homeTeamScore > awayTeamScore then 0 else 1 end
       end) team1Wins,
       sum(case when hometeam > awayteam
          then case when homeTeamScore > awayTeamScore then 1 else 0 end else case when homeTeamScore > awayTeamScore then 0 else 1 end
       end) team2Wins
FROM ow_sports_games 
GROUP BY least(homeTeam, awayTeam),
         greatest(homeTeam, awayTeam)

还有什么比这更好的方法来获得更好的SQL吗？

SQL小提琴：http://sqlfiddle.com/#!2/10326/4/1

修改

一些示例数据可以更详细地解释我的要求：

HOMETEAM    HOMETEAMSCORE   AWAYTEAM    AWAYTEAMSCORE
18          1               22              0
22          2               18              1
18          3               22              2
12          0               13              0

对于18,22队，输出应为2-1，因为18队有2场胜利，22队有1场

对于12队和13队，输出应为0-0，因为没有比赛结束。

OUTPUT示例解释整体情况：

HomeTeam      AwayTeam     Records
18             22          2-1
22             18          1-2
12             13          0-0

Answer 1

这与问题陈述中的输出相匹配（前3列是相同的，接下来的两列是用于排序的，并确保我们在没有玩的时候考虑但是有记录。请参阅http://sqlfiddle.com/#!2/10326/43

SELECT DISTINCT hometeam, awayteam
    , CONCAT(IF(hometeam = LEAST(hometeam, awayteam),team1wins, team2wins),' - ', IF(awayteam = LEAST(hometeam, awayteam),team1wins, team2wins)) AS Head2HeadRecord
    , CONCAT(LEAST(hometeam, awayteam), GREATEST(hometeam, awayteam)) AS surrogateSort
    , notplayed
FROM ow_sports_games 
JOIN (SELECT LEAST(hometeam, awayteam) AS team1
       ,GREATEST(hometeam, awayteam) AS team2
       ,SUM(IF(LEAST(hometeam, awayteam) = hometeam AND homeTeamScore > awayTeamScore, 1,
                IF(LEAST(hometeam, awayteam) = awayteam AND awayTeamScore > homeTeamScore,1,0) 
              )
            ) AS team1Wins
      ,SUM(IF(GREATEST(hometeam, awayteam) = hometeam AND homeTeamScore > awayTeamScore, 1,
                IF(GREATEST(hometeam, awayteam) = awayteam AND awayTeamScore > homeTeamScore,1,0) 
              )
            ) AS team2Wins  
       ,SUM(IF(homeTeamScore=0 AND awayTeamScore=0,1,0)) AS notPlayed
      FROM ow_sports_games 
      GROUP BY team1, team2) AS trecords
  ON LEAST(hometeam, awayteam) = team1
    AND GREATEST(hometeam, awayteam) = team2
ORDER BY surrogateSort, hometeam,awayteam;

用于获取2个团队的匹配记录的SQL

1 个答案: