Question

我有下表的数据

+---------+--------+--------+
| Trans   | Status | Step   |
+---------+--------+--------+
| ABCDE   | Comple | 1
+---------+--------+--------+
| ABCDE   | Error  | 2
+---------+--------+--------+
| FGHIJ   | Comple | 1
+---------+--------+--------+
| FGHIJ   | Comple | 2
+---------+--------+--------+
| KLMNO   | Comple | 1
+---------+--------+--------+
| KLMNO   | Comple | 2
+---------+--------+--------+

我只想删除trans和status ='comple'的计数与trans的计数相同的记录

我可能会做一个游标和循环，但这是我不想做的事。

按照计数的思路思考，但可能相距甚远。

谢谢

我只想删除FGHIJ和KLMNO，因为我知道已完成所有步骤。

我要保留abcde，因为并非所有步骤都已完成

Answer 1

这是您想要的吗？

--delete 
select *
from yourtable t
where not exists
(
    select 1
    from yourtable t2
    where t1.Trans=t2.Trans
    and status<>'Comple'
)

首先使用它，以确保要删除的内容，然后注释掉SELECT并取消注释删除

Answer 2

DELETE FROM tbl
WHERE  Trans IN ( SELECT trans
                  FROM   tbl
                  GROUP  BY Trans
                  HAVING COUNT(*) = SUM(CASE WHEN status = 'Comple' THEN 1 ELSE 0 END) )

它删除行（通过对Trans进行过滤），其中一组trans中的行数等于具有Comple状态的该组中的行数

http://sqlfiddle.com/#!18/1768b/10

Answer 3

尝试一下

DECLARE @Data AS TABLE (Trans Varchar(10)   , Status  Varchar(10) , Step INT   )
INSERT INTO @Data
SELECT 'ABCDE', 'Comple' , 1 UNION ALL
SELECT 'ABCDE', 'Error'  , 2 UNION ALL
SELECT 'FGHIJ', 'Comple' , 1 UNION ALL
SELECT 'FGHIJ', 'Comple' , 2 UNION ALL
SELECT 'KLMNO', 'Comple' , 1 UNION ALL
SELECT 'KLMNO', 'Comple' , 2

SELECT * FROM @Data

;WITH CTe
AS
(
SELECT * , ROW_NUMBER()OVER(PArtition by Trans   , [Status] ORDER BY  Trans) AS TwocountsMatch
FROM @Data
)
DELETE FROM CTe WHERE TwocountsMatch=2 AND [Status]='Comple'


SELECT * FROM @Data

演示结果：http://rextester.com/TYK92230

Answer 4

如果我对您的理解正确，那么您想删除所有[Trans]行，如果所有这些行[status]是'Comple'吗？

DECLARE @Data AS TABLE (Trans Varchar(10)   , Status  Varchar(10) , Step INT   )

INSERT INTO @Data
SELECT 'ABCDE', 'Comple' , 1 UNION ALL
SELECT 'ABCDE', 'Error'  , 2 UNION ALL
SELECT 'FGHIJ', 'Comple' , 1 UNION ALL
SELECT 'FGHIJ', 'Comple' , 2 UNION ALL
SELECT 'KLMNO', 'Comple' , 1 UNION ALL
SELECT 'KLMNO', 'Comple' , 2

SELECT * FROM @Data;

WITH
  summarised
AS
(
  SELECT
    * ,
    COUNT(*) OVER (PARTITION BY [trans]          )   AS count_trans,
    COUNT(*) OVER (PARTITION BY [trans], [status])   AS count_trans_status
  FROM
    @Data
)
DELETE
  summarised
WHERE
  [status] = 'Comple'
  AND count_trans = count_trans_status
;

SELECT * FROM @Data

如果两个计数匹配，则删除记录

4 个答案: