Question

我是Django和Python的新手。

当我将我的代码从我的本地开发盒移动到Webfaction上的我的网站时，它似乎打破了我的代码。如果我然后从我的主应用程序views.py中删除（ context_instance = RequestContext（request）），它似乎可以解决问题。如果以后我把线放回来就可以了。

return render_to_response('template.html', {"var": var},**context_instance=RequestContext(request)**)

来自webhost的错误电子邮件：

Traceback (most recent call last):

 File "/home/hhadmin69/webapps/django/lib/python2.5/django/core/handlers/base.py", line 92, in get_response
   response = callback(request, *callback_args, **callback_kwargs)

 File "/home/hhadmin69/webapps/django/hhv3/article/views.py", line 32, in post_index
   return render_to_response('article/post_index.html', {"posts": posts},context_instance=RequestContext(request))

 File "/home/hhadmin69/webapps/django/lib/python2.5/django/template/context.py", line 107, in __init__
   self.update(processor(request))

 File "/home/hhadmin69/webapps/django/hhv3/context_processors.py", line 12, in latest_tweet
   tweet = twitter.Api().GetUserTimeline( settings.TWITTER_USER )[0]

 File "build\bdist.win32\egg\twitter.py", line 1414, in GetUserTimeline

 File "build\bdist.win32\egg\twitter.py", line 2032, in _FetchUrl

 File "/usr/local/lib/python2.5/urllib2.py", line 387, in open
   response = meth(req, response)

 File "/usr/local/lib/python2.5/urllib2.py", line 498, in http_response
   'http', request, response, code, msg, hdrs)

 File "/usr/local/lib/python2.5/urllib2.py", line 425, in error
   return self._call_chain(*args)

 File "/usr/local/lib/python2.5/urllib2.py", line 360, in _call_chain
   result = func(*args)

 File "/usr/local/lib/python2.5/urllib2.py", line 506, in http_error_default
   raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)

HTTPError: HTTP Error 400: Bad Request


 'SERVER_SOFTWARE': 'Apache/2.2.12 (Unix) mod_wsgi/2.5 Python/2.5.4',

context_processors.py

from datetime import datetime
from django.conf import settings
from django.core.cache import cache
import twitter

from django.template import Library, Node, TemplateSyntaxError

def latest_tweet( request ):
    tweet = cache.get( 'tweet' )

    if tweet:
        return {"tweet": tweet}
    try:
        tweet = twitter.Api().GetUserTimeline( settings.TWITTER_USER )[0]
        tweet.date = datetime.strptime( tweet.created_at, "%a %b %d %H:%M:%S +0000 %Y" )
        cache.set( 'tweet', tweet, settings.TWITTER_TIMEOUT )
    except (RuntimeError, TypeError, NameError):
        pass    

    return {"tweet": tweet}

谢谢!!

Answer 1

您的追溯清楚地表明问题出在twitter {API}的GetUserTimeline

您的TWITTER_USER

中是否定义了settings？

Answer 2

它不是RequestContext - 上下文只会触发实际上失败的高频查询。如果你把线放回去了吗？这可能只意味着您的Twitter查找问题不一致，因为任何HTTP查找都是如此，因此您应该通过处理IOError（HTTPError的父项URLError来处理可能的网络问题。由urllib2抛出的{1}}。

try:
    tweet = twitter.Api().GetUserTimeline( settings.TWITTER_USER )[0]
except IOError, e:
    logging.error(e) #or just print, dont know how you log

准确分析失败的方式和时间并尝试找出问题。查看urllib2尝试访问的实际URL也可能有所帮助。

Answer 3

一旦我扩展了例外以包含以下内容，它就解决了我的问题。非常感谢！

except (IOError, urlopen, URLError, HTTPError):
       pass

Django：RequestContext问题？

3 个答案: