我似乎无法访问django模板中的请求对象。
这是我的settings.py文件的一部分:
import django.conf.global_settings as DEFAULT_SETTINGS
TEMPLATE_CONTEXT_PROCESSOR = DEFAULT_SETTINGS.TEMPLATE_CONTEXT_PROCESSORS + (
'django.core.context_processors.request',
)
urls.py
urlpatterns = patterns('',
url(r'^event/create/$', EventCreateView.as_view(), name='create_event'),
url(r'^event/update/(?P<pk>\d+)/$', EventUpdateView.as_view(), name='update_event'),
url(r'^event/delete/(?P<pk>\d+)/$', EventDeleteView.as_view(), name='delete_event'),
)
views.py
from django.views.generic import CreateView, UpdateView, DeleteView
from events.models import Event
from events.forms import EventForm
class EventCreateView(CreateView):
model = Event
form_class = EventForm
class EventUpdateView(UpdateView):
model = Event
form_class = EventForm
class EventDeleteView(DeleteView):
model = Event
forms.py
from django.forms import ModelForm
from events.models import Event
class EventForm(ModelForm):
class Meta:
model = Event
event_form.html(适用于CreateView / UpdateView)
{% block content %}
<form action='{{ request.get_full_path }}' method='post'>
{% csrf_token %}
<table>
{{ form.as_table }}
</table>
<input type='submit' value='Create event!' />
</form>
{% endblock %}
上面,request.session似乎什么都不做。我已经尝试过查看文档和类似的问题,但似乎没有任何工作。有什么想法吗?
提前致谢。
答案 0 :(得分:3)
你有一个错字,在TEMPLATE_CONTEXT_PROCESSORS结束时缺少'S',也许就在你的问题中?设置应该是:
TEMPLATE_CONTEXT_PROCESSORS = ("django.contrib.auth.context_processors.auth",
"django.core.context_processors.debug",
"django.core.context_processors.i18n",
"django.core.context_processors.media",
"django.core.context_processors.static",
"django.core.context_processors.tz",
"django.contrib.messages.context_processors.messages",
"django.core.context_processors.request",)
,而不是TEMPLATE_CONTEXT_PROCESSOR = ...
。我更喜欢完全覆盖设置,因此很清楚什么是活动的(例如,您可能希望在生产中禁用调试)。
答案 1 :(得分:1)
您使用Django的Session框架吗?然后是的,request.session
将什么都不做,因为a会话是类似dict的对象而模板引擎不知道如何呈现它。