替换字符串中的单词 - 但有两个不同的单词：Python3

Question

尝试获取它，使得输入与原始字符串中出现的特定单词的次数相同，并将其替换为输入的每个单词。

def replace_parts_of_speech (replaced, part_of_speech):
    '''Finds and replaces parts of speech with words '''
    new_line=''

    for i in range (replaced.count(part_of_speech)):
        new=input('Enter '+ part_of_speech +':') 
        new_line = replaced.replace(part_of_speech,new,1)


    return new_line

Answer 1

问题在于，每次循环播放时，您都会创建一个全新的new_line，忽略之前的new_line，然后返回到原来的replaced。因此，循环完成后，只有最后一个替换才会可见。

for i in range (replaced.count(part_of_speech)):
    new=input('Enter '+ part_of_speech +':') 
    new_line = replaced.replace(part_of_speech,new,1)

所以，第二个替换忽略了第一个。

你想要做的是：

new_line = replaced
for i in range (replaced.count(part_of_speech)):
    new=input('Enter '+ part_of_speech +':') 
    new_line = new_line.replace(part_of_speech,new,1)

---

同一问题的简化示例可能更容易理解：

start = 0
current = 0
for i in range(5):
    current = start + i
print(current)

这将只打印4。但现在：

start = 0
current = start
for i in range(5):
    current = current + i
print(current)

这将打印10。