Question

number = 96154# Replace ??? with a value of your choice.
sequence_len = 3 # Replace ??? with a value of your choice.
sum=0
numbstr=str(number)
digitlist=[]

for digit in numbstr:
 digitlist.append(int(digit))

while sum!=10 or len(digitlis)<sequence_len:
sum=0
if len(digitlist)>=3:
    for i in range(0,3):
        sum=sum+digitlist[i]
    del digitlist [i]

print sum

代码需要检查是否存在以下数字序列的总和（例如3），其总和为10并打印有关它的信息

我的代码出了什么问题？

Answer 1

在for循环之后，i将为3.因此del digitlist [i]将删除第3个元素而不是第1个元素。将其替换为del digitlist [0]。此外，您的while语句条件中的len(digitlis)<sequence_len应为len(digitlis)>=sequence_len。最后，有一个拼写错误; len(digitlis)应为len(digitlist)。

更正后的代码：

number = 96154# Replace ??? with a value of your choice.
sequence_len = 3 # Replace ??? with a value of your choice.
sum=0
numbstr=str(number)
digitlist=[]

for digit in numbstr:
 digitlist.append(int(digit))
# len(digitlis)<sequence_len → len(digitlist)>sequence_list
while sum!=10 or len(digitlist)>sequence_len: # 
    sum=0
    if len(digitlist)>=3:
        for i in range(0,3):
            sum=sum+digitlist[i]
        del digitlist [0] # del digitlist [i] → del digitlist [0]

print sum

使用Python功能的更紧凑版本：

DESIRED_SUM=10
number = 96154# Replace ??? with a value of your choice.
sequence_len = 3 # Replace ??? with a value of your choice.
digit_list = list(map(int,str(number)))
# Note that if len(digit_list)-sequence_len+1 is negative, the range function will return an empty list, making the generator comprehension empty. any() returns False on an empty iterator (a generator is an iterator).
indexes = [i for i in range(len(digit_list)-sequence_len+1) if sum(digit_list[i:i+sequence_len])==DESIRED_SUM]
if len(indexes) > 0:
    print "{sequence_len} consecutive digits in {number} have a sum of {DESIRED_SUM}.".format(**vars())
else:
    print "No {sequence_len} consecutive digits have a sum of {DESIRED_SUM}.".format(**vars())

Answer 2

首先：

digitlist=[]

for digit in numbstr:
 digitlist.append(int(digit))

可以简单地替换为：

digitlist = [int(i) for i in str(number)]

要计算总和，只需调用列表中的sum函数：

sum(digitlist)

Answer 3

有几个问题：

...len(digitlis)<sequence_len...，您的变量缺少t。
其次，我不知道你的代码是做什么的，逻辑不是非常直观。

但是，这是一个简单的程序，可以完成你想要它做的事情，并且我保持尽可能简单：

number = 343703  # Replace ??? with a value of your choice.
sequence_len = 3  # Replace ??? with a value of your choice.
numbstr = str(number)
digitlist = []

# Appending all the numbers to a list
for digit in numbstr:
    digitlist.append(int(digit))

# Looping over all the variables in digitlist, i is the index
for i, _ in enumerate(digitlist):
    # If the index, i is 2 less than the length of the list
    if i < len(digitlist) - 2:
        # Adding the term and the next two terms after that
        if digitlist[i] + digitlist[i+1] + digitlist[i+2] == 10:
            # Printing the list
            print digitlist[i:i+3]

Working example.

以下数字的总和

3 个答案: