不同条件下的总价值

Question

我希望为某些不同类型的作业获取某些表的聚合值。我可以将这3个查询合并到一个查询中吗？

SELECT
    COUNT(*) AS totaljobs,
    SUM(filesize) AS totalfilesize
FROM Job

SELECT
    COUNT(*) AS assignedjobs,
    SUM(filesize) AS assignedjobs
FROM Job
JOIN Assignment ON Assignment.job_id = Job.id

SELECT
    COUNT(*) AS unassignedjobs,
    SUM(filesize) AS unassignedjobs
FROM Job
LEFT JOIN Assignment ON Assignment.job_id = Job.id
WHERE Assignment.job_id IS NULL

查询的行为与您预期的一样，例如： totaljobs = assignedjobs + unassignedjobs。我觉得有一种方法可以在一个查询中更有效地完成它，但我不知道如何。

Answer 1

试试这个

SELECT
    SUM(case when Assignment.job_id IS NOT NULL then 1 else 0 end) AS assignedjobs,
    SUM(case when Assignment.job_id IS NULL then 1 else 0 end) AS unassignedjobs,
    COUNT(*) as totaljobs
FROM Job
LEFT JOIN Assignment ON Assignment.job_id = Job.id